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mojhsa [17]
2 years ago
12

How is 4 2/7 to an improper fraction

Mathematics
1 answer:
Triss [41]2 years ago
6 0

(4×7) + 2

30/7

hope it helps...!!!

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HELPPPP ILL: MARK BRAINLIEST IF I CAN OR GET TWO ANSWERS
borishaifa [10]

Answer:

o is the answer as it passes through origin

4 0
2 years ago
Two trains leave stations 442 miles apart at the same time and travel toward each other. one train travels at 90 miles per hour
pickupchik [31]
Let x and (442-x) represent the distance of the trains traveled. X/90 mph=442-x/80 mph
Cross multiply 80×x =90(442-x)
80x=90×442-90x
170x=90×442
X= 90×442/170
X=234, distance traveled by train going 90mph
234mi/90mph = 2.6 hr, time it takes for the two trains tok meet.
Checking your answer:
90×2.6+80×2.6=234mi+208mi = 442mi
6 0
3 years ago
Please help! Will mark the brainliest!
sesenic [268]
The domain is the set of all possible x-values which will make the function valid.
f(x) = \frac{3}{x-2} \ \ \ \ , \ g(x) =  \sqrt{x-1}
For the given function :
The denominator of a fraction cannot be zero
The number under a square root sign must be Non negative


(a)

(1) The domain of f ⇒⇒⇒ R - {2}

Because ⇒⇒⇒  x - 2 = 0  ⇒⇒⇒ x = 2

(2) The domain of g ⇒⇒⇒ [1,∞)
Because: x - 1 ≥ 0 ⇒⇒⇒ x ≥ 1

(3) f + g = \frac{3}{x-2} + \sqrt{x-1}
The domain of (f+g) ⇒⇒⇒ [1,∞) - {2}
because: x-2 = 0 ⇒⇒⇒ x = 2   and    x - 1 ≥ 0 ⇒⇒⇒ x ≥ 1


(4) f - g = \frac{3}{x-2} - \sqrt{x-1}
The domain of (f-g) ⇒⇒⇒ [1,∞) - {2}
because: x-2 = 0 ⇒⇒⇒ x = 2   and    x - 1 ≥ 0 ⇒⇒⇒ x ≥ 1


(5) f * g = \frac{3}{x-2} * \sqrt{x-1} = \frac{3 \sqrt{x-1}}{(x-2)}
The domain of (f*g) ⇒⇒⇒ [1,∞) - {2}
because: x-2 = 0 ⇒⇒⇒ x = 2   and    x - 1 ≥ 0 ⇒⇒⇒ x ≥ 1

(6) f * f = \frac{3}{x-2} * \frac{3}{x-2} = \frac{9}{(x-2)^2}
The domain of ff ⇒⇒⇒ R - {2}

Because ⇒⇒⇒  x-2 = 0  ⇒⇒⇒ x = 2

(7) \frac{f}{g} =   \frac{\frac{3}{x-2} }{ \sqrt{x-1} } =  \frac{3}{(x-2) \sqrt{x-1}}
The domain of (f/g) ⇒⇒⇒ (1,∞) - {2}
because: x-2 = 0 ⇒⇒⇒ x = 2   and    x - 1 > 0 ⇒⇒⇒ x > 1

(8) \frac{g}{f} =  \frac{ \sqrt{x-1} }{ \frac{3}{x-2} } =  \frac{1}{3} (x-2) \sqrt{x-1}
The domain of (g/f) ⇒⇒⇒ [1,∞) - {2}
Because: x - 2 = 0 ⇒⇒⇒ x = 2   and   x - 1 ≥ 0  ⇒⇒⇒ x ≥ 1
===================================================
(b)


(9) (f + g)(x) = \frac{3}{x-2} + \sqrt{x-1}


(10) (f - g)(x) = \frac{3}{x-2} - \sqrt{x-1}


(11) (f * g)(x) = \frac{3}{x-2} * \sqrt{x-1} = \frac{3 \sqrt{x-1}}{(x-2)}


(12) (f * f)(x) = \frac{3}{x-2} * \frac{3}{x-2} = \frac{9}{(x-2)^2}


(13) \frac{f}{g} =   \frac{\frac{3}{x-2} }{ \sqrt{x-1} } =  \frac{3}{(x-2) \sqrt{x-1}}


(14) (\frac{g}{f})(x) =  \frac{ \sqrt{x-1} }{ \frac{3}{x-2} } =  \frac{1}{3} (x-2) \sqrt{x-1}



7 0
2 years ago
Suppose that a recent poll of American households about pet ownership found that for households with pets, 45% owned a dog, 34%
11111nata11111 [884]

Answer: 0.091125

Step-by-step explanation:

Given : P(dog) = 0.45

If 3 households are selected randomly and with replacement and the ownership is mutually exclusive.

Then , probability that all three randomly selected households own a dog = (0.45)^3=0.091125

Hence, required probability = 0.091125

3 0
2 years ago
How many square centimetres are there in the surface area of a solid cube of side 1 metre?
Bogdan [553]

Answer:

60,000 cm^2.

Step-by-step explanation:

1 metre = 100 centimetres.

Area of one side of the cube = 1*1 metre = 100*100

= 10,000 cm^2.

Now there are 6 sides on a cube so the total surface area

= 6 * 10,000 = 60,000 cm^2

7 0
2 years ago
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