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g100num [7]
3 years ago
11

A box contains seven green marbles, six blue marbles and eight orange marbles. Without looking, you choose two marbles out of th

e bag. What is the probability that both be green if you don’t replace the marble after the first pick?
Mathematics
1 answer:
Delvig [45]3 years ago
5 0

Answer:

The probability is 0.1  (or 10%)

Step-by-step explanation:

The probability is the ratio of the number of favorable outcomes and the total number of possible outcomes.

The favorable count is determined as follows: we are considering Green marbles. There are 7 of them in the box, so 7 possible picks at the first draw. Since you don't replace the pick, at the next drawing there are only 6 Green ones. So for each of the 7 possible first picks, there are 6 possible second picks: number of possibilities is 7 by 6 = 42.

The total number of possible drawings, irrespective of color is determined as follows: there are 21 marbles in total at first drawing, and 20 at second. So, for each first pick there are 20 possibilities, i.e., total number is 21 by 20 = 420

The probability is therefore:

P = 42 / 420 = 1 / 10 = 0.1  (or 10%)

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