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user100 [1]
3 years ago
11

Taking a test will mark braniniliest

Mathematics
2 answers:
Vlad [161]3 years ago
8 0

Answer:

whats the question?

erastovalidia [21]3 years ago
5 0

Answer:

Five hundred and three, you multiply the 5 by the 10 to the second power and get 500 because 10 to the second power is 10x10 which is 100, then add the three

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An equilateral ∆ has sides of length 16 cm. Find the length of an altitude.
inn [45]

The length of the altitude is 8\sqrt{3}

Explanation:

Let ABC be an equilateral triangle.

It has sides of length 16 cm

Let AD be the altitude of the triangle.

We need to determine the length of an altitude.

Let AC = 16 cm and CD = 8 cm

Let us consider the right angled triangle ADC

Using the Pythagorean theorem, we have,

AC^2=AD^2+DC^2

Substituting the values, we get,

 16^2=AD^2+8^2

 256=AD^2+64

 192=AD^2

8\sqrt{3}=AD

The length of the altitude is 8\sqrt{3}

5 0
3 years ago
44. Express each of these system specifications using predicates, quantifiers, and logical connectives. a) Every user has access
DENIUS [597]

Answer:

a. ∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))

b. FileSystemLocked → ∀x Access(x, SystemMailbox)

c. ∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))

d. ∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

Step-by-step explanation:

a)  

Let the domain be users and mailboxes. Let User(x) be “x is a user”, let Mailbox(y) be “y is a mailbox”, and let Access(x, y) be “x has access to y”.  

∀x (User(x) → (∃y (Mailbox(y) ∧ Access(x, y))))  

(b)

Let the domain be people in the group. Let Access(x, y) be “x has access to y”. Let FileSystemLocked be the proposition “the file system is locked.” Let System Mailbox be the constant that is the system mailbox.  

FileSystemLocked → ∀x Access(x, SystemMailbox)  

(c)  

Let the domain be all applications. Let Firewall(x) be “x is the firewall”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”.  

∀x ∀y ((Firewall(x) ∧ Diagnostic(x)) → (ProxyServer(y) → Diagnostic(y))  

(d)

Let the domain be all applications and routers. Let Router(x) be “x is a router”, and let ProxyServer(x) be “x is the proxy server.” Let Diagnostic(x) be “x is in a diagnostic state”. Let ThroughputNormal be “the throughput is between 100kbps and 500 kbps”. Let Functioning(y) be “y is functioning normally”.  

∀x (ThroughputNormal ∧(ProxyServer(x)∧ ¬Diagnostic(x))) → (∃y Router(y)∧Functioning(y))

4 0
3 years ago
ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions
4vir4ik [10]

Answer:

the 3rd one

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Please I need this answer with working... <br> Log 91 - Log 13 /Log 245 - Log 5
kakasveta [241]
The answer is: 1.49
i used a calculator.
7 0
3 years ago
Read 2 more answers
WHAT IS THIS???????​
kodGreya [7K]

Answer:

i think you have to mark where the dog leashes go on the line plot based on their length?? for example, a 3 foot dog leash is on the <em>list</em>, so maybe you're supposed to put an X or something above the number 3 on the <em>line plot</em>? so sorry if this didn't help..

7 0
3 years ago
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