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anyanavicka [17]
2 years ago
10

Question 2 (Essay Worth 10 points)

Mathematics
1 answer:
Soloha48 [4]2 years ago
5 0

Answer:

Account A: Decreasing at 8 % per year

Account B: Decreasing at 10.00 % per year

Account B shows the greater percentage change

Step-by-step explanation:

Part A: Percent change from exponential formula

f(x) = 9628(0.92)ˣ

The general formula for an exponential function is

y = ab^x, where

b = the base of the exponential function.

if b < 1, we have an exponential decay function.

ƒ(x) decreases as x increases.

Account A is decreasing each year.

We can rewrite the formula for an exponential decay function as:

y = a(1 – b)ˣ, where

1 – b = the decay factor

b = the percent change in decimal form

If we compare the two formulas, we find

0.92 = 1 - b

b = 1 - 0.92 = 0.08 = 8 %

The account is decreasing at an annual rate of 8 %.The account is decreasing at an annual rate of 10.00 %.

Account B recorded a greater percentage change in the amount of money over the previous year.

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Urn 1 contains two white balls and one black ball, while urn 2 contains one whiteball and ve black balls. One ball is drawn at r
matrenka [14]

Answer:

4/5 is the probability of white ball from urn 2

Step-by-step explanation:

Correct statement of the question is ;

Urn 1 contains two white balls and one black ball, while urn 2 contains one white bait and five black balls. One ball is drawn at random from urn 1 and placed in urn 2. A ball is then drawn from urn 2. It happens to be white. What is the probability that the transferred ball was white?

We solve it ;

Probability of taking out balls from urn 1

<u>a) for white ball</u>

P(w_{1} )=\frac{2}{3}

 

<u>b) for balck ball</u>

P(b_{1} )= \frac{1}{3}

If one ball is taken from urn 1 and put in urn 2 (which readily contains one white and five black balls)

Probability of taking out balls from urn 2

<u>a) for white ball</u>

P(w_{2} )=P(\frac{w_{2} }{w_{1} } ).P(w_{1} )+P(\frac{w_{2} }{b_{1} } ).P(b_{1} )

=\frac{2}{7} . \frac{2}{3} + \frac{1}{7}. \frac{1}{3} =\frac{5}{21}

Then the probability that white ball was transferred from urn 1 to urn 2 is;

P(\frac{white ball transfer }{w_{2} } )= \frac{P(\frac{w_{2} }{w_{1} } ).P(w_{2} )}{P(w_{2}) }

=\frac{ \frac{2}{7}.\frac{2}{3}  }{\frac{5}{21} }

=\frac{4}{5}

So, the probability that white ball is drawn from urn 2 is 4/5

4 0
3 years ago
What u isf(x)=x^2-10x+24?
pentagon [3]
F(x) = x² - 10x + 24
opens up because coefficient of x² is positive
crosses x-axis at x = 6 and x = 4 
crosses y-axis at y = 24
vertex is a minimum at (5, -1)
3 0
3 years ago
Write the equation of a line that passes through points (10, -1) and (8,0).
blondinia [14]

Answer:

you figure the equation out, but the slope is 1/10

Step-by-step explanation:

3 0
4 years ago
Please answer this question ONLY IF YOU KNOW THE ANSWER!! 50 points and brainliest!
ryzh [129]

Answer:

Fair game

Step-by-step explanation:

Let us find the sample space.  It is the sum of the two spins

1+1 1+2 1+3  1+4 1+5 1+6

2+1 2+2  2+3  2+4 2+5 2+6

3+1 3+2 3+3 3+4 3+5 3+6

4+1  4+2  4+3  4+4 4+5 4+6

5+1  5+2 5+3 5+4 5+5 5+6

6+1 6+2 6+3 6+4 6+5 6+6

Adding

2,3,4,5,6,7

3,4,5,6,7,8

4,5,6,7,8,9

5,6,7,8,9,10

6,7,8,9,10,11

7,8,9,10,11,12

P(2) = 1/36

p(3) = 2/36

p(4) = 3/36

p(5) = 4/36

p(6) = 5/36

p(7) = 6/36

p(8) = 5/36

p(9) = 4/36

p(10) = 3/36

p(11) = 2/36

p(12) = 1/36

Player A wins if the sum is even

P(2,4,6,8,10,12) = P(2)+P(4)+P(6)+P(8)+P(10) + P (12) because the events are independent

               = 1/36 + 3/36+5/36+5/36+3/36 +1/36= 18/36 = 1/2


Player B wins if the sum is odd

P(3,5,7,9,11) = P(3)+P(5)+P(7)+P(9)+p(11) because the events are independent

               = 2/36 + 4/36+6/36 +4/36+2/36= 18/36 = 1/2

The probabilities are the same, so this is a fair game

7 0
4 years ago
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kipiarov [429]

Answer:

The answer would be G.

Step-by-step explanation.

To get your answer, you have to pick two points. Ex: (0,4) (4,1)

Put them into the slop equation: slope= y2-y1/x2-x1

slope:1-4/4-0= -3/4

5 0
3 years ago
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