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Semmy [17]
3 years ago
6

C = -(F -- 32) The equation above shows how temperature F, measured in degrees Fahrenheit, relates to a temperature C, measured

in degrees Celsius. Based on the equation, which of the following must be true? 1. A temperature increase of 1 degree Fahrenheit is equivalent to a temperature increase of of degree Celsius. 9 II. A temperature increase of 1 degree Celsius is equivalent to a temperature increase of 1.8 degrees Fahrenheit. III . A temperature increase of degree Fahrenheit is equivalent to a temperature increase of 1 degree Celsius.
A)lonly

B) Il only

C) Ill only

D) land ll only​
Mathematics
1 answer:
Goryan [66]3 years ago
4 0

Answer:

Step-by-step explanation:

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The averge per mile is 4.06
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rhombus has sides of length 10 cm. and the angle between two adjacent sides is 76 degrees. Find the lengths of the other diagona
lisabon 2012 [21]
Let the length of one of the diagonals be 2x and the other be 2y, then
cos (76/2) = x/10
x = 10 cos 38 = 7.88 cm

sin (76/2) = y/10
y = 10 sin 38 = 6.16 cm
3 0
4 years ago
Can someone please help me out! and please explain your answer, and how you got it right! thank you so much!
Contact [7]

It is

24x - 30

The equation for area of a trapezoid is

\frac{1}{2} (a + b) \times h

Substituting our values in

\frac{1}{2} (3x + 7 + 5x - 3) \times 6

We can then simplify the expression

\frac{1}{2} (8x - 10) \times 6 \\ (4x - 5) \times 6 \\ 24x - 30

8 0
3 years ago
At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?
hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

d*sin(\theta) = m\lambda

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle              

At the first-order maximum (m=1) at 20.0 degrees we have:

\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342

Now, to produce a second-order maximum (m=2) the angle must be:

sin(\theta) = \frac{\lambda}{d}*m

\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.    

I hope it helps you!                                                        

6 0
3 years ago
WILL GIVE BRAINLIEST AND THANKS AND RATING!
Lorico [155]
8 is 6.2
9 is 7
The pattern here is +0.8.
4.6 - 3.8=0.8
5.4-4.6=0.8, and so on
6 0
3 years ago
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