Answer:
∠1 = 124 degrees
Step-by-step explanation:
Vertical angles are always congruent
So ∠1 = ∠2
Answer:
25
Explanation:
In order to solve this the easiest way you can use equivalent fractions.
![\frac{4}{5} = \frac{20}{?}\\](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B5%7D%20%3D%20%5Cfrac%7B20%7D%7B%3F%7D%5C%5C)
Since 4 times 5 equals 20 we can multiply 5 times 5 to get our answer.
![\frac{4}{5} * \frac{5}{5} = \frac{20}{25}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B5%7D%20%2A%20%5Cfrac%7B5%7D%7B5%7D%20%3D%20%5Cfrac%7B20%7D%7B25%7D)
25 is the answer. But, if we couldn't have gotten to 20 through the multiplication we could use a proportion. That would look like the initial problem but instead of a "?" we would use a variable. I will use <em>t</em> for total.
![\frac{4}{5} = \frac{20}{t}\\](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B5%7D%20%3D%20%5Cfrac%7B20%7D%7Bt%7D%5C%5C)
So now we have our problem set up. The next step is to cross multiply. 4 by <em>t</em> and 5 by 20.
![4t = 5 * 20\\4t = 100\\](https://tex.z-dn.net/?f=4t%20%3D%205%20%2A%2020%5C%5C4t%20%3D%20100%5C%5C)
And now we can solve it like a normal algebra problem.
![\frac{4}{4}t = \frac{100}{4}\\t = 25](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B4%7Dt%20%3D%20%5Cfrac%7B100%7D%7B4%7D%5C%5Ct%20%3D%2025)
Either way, we get 25.
Answer:
trifi
Step-by-step explanation:
4t3 a good relationship is the same way you could get to the claire family thing you want but I have different feelings about the same way
This is the concept of scale factors. Given that Joaquin has reduce the dimensions of a picture by scale factor of 0.3 and the original dimension was 10 cm length by 10 cm width, the new dimension will be:
New length=(old length)×(scale factor)
New width=(old width)×(scale factor)
Plugging the values in the above formulas we get:
New length=15x0.3=4.5 cm
New width=10×0.3=3 cm
Answer: We support the null hypothesis.
Step-by-step explanation:
Given : The purpose of the study was to determine whether the mean weekly number of hours that Internet users in that age group spend online differs from the mean for Internet users in general which is 12.50 hours.
The set of hypothesis for the given claim :-
![H_0:\mu=12.50\\\\ H_a:\mu\neq12.50](https://tex.z-dn.net/?f=H_0%3A%5Cmu%3D12.50%5C%5C%5C%5C%20H_a%3A%5Cmu%5Cneq12.50)
A 95% confidence interval for the mean weekly number of hours that Internet users in that age group spend online was calculated to be (11.439 , 12.577).
Since 12.50 contained in the 95% confidence interval (11.439 , 12.577).
Therefore, we support the null hypothesis.
So the final conclusion will be, we have evidence to support the claim that Internet users in that age group spend online differs from the mean for Internet users in general which is 12.50 hours.