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2 years ago

Help me please with this math question! giving brainliest to the correct answer

Mathematics

2 answers:

Arlecino [84]2 years ago

8 0

Answer:

12.5

Step-by-step explanation:

All I really did was divide the circumference by pi to get the diameter which you end up dividing it by two to get the radius.

FrozenT [24]2 years ago

6 0

Answer:

12.5

Step-by-step explanation: To get the answer you have to divide the circumfrence by the diamenter to get your answer hope this helps good luck :)

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Manuel just bought a new television for $629.00.He made down payment of $57.00 and will pay monthly payments of $26.00 until it

r-ruslan [8.4K]

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6 0

3 years ago

Read 2 more answers

F(x) =2x^2+4x+5<br> Find: f(a)

MA_775_DIABLO [31]

Answer:

F(a) =2a^2+4a+5

Step-by-step explanation:

just put x= a

5 0

3 years ago

Among the four northwestern states, Washington has 51% of the total population, Oregon has 30%, Idaho has 11%, and Montana has 8

morpeh [17]

Answer:

Step-by-step explanation:

H₀ : The distribution of the sample agrees with the population distribution.

H₁ : the distribution of the does not agree with the population distribution.

Using the Chi-square test statistics

we will compute the expected frequencies

Now expected frequency for Washington will be

Fe = Npi = 1000×51% = 5100

expected frequency for Oregon

Fe = Npi = 1000×30% = 300

expected frequency for Idaho

Fe = Npi = 1000×11% = 110

expected frequency for Montana

Fe = Npi = 1000×8% = 80

The Chi=square test statistics is;

x² = ∑ [ (Fo - Fe)² / Fe )

now we substitute

Given our Fo ( 450 in Washington, 340 in Oregon, 150 in Idaho, and 60 in Montana) from the question

x² = (450-510)²/510 + (340-300)²/300 + (150-110)²/110 + (60-80)²/80

x²= 31.9376

so the chi-square test statistics is 31.9376

Now the chi-square critical value

first we compute for degree of freedom

d.f = k -1 = 4 - 1 = 3

So from the critical value table, degree of freedom 3 and significance level 0.05,

the chi-square critical value is 7.8147

Therefore chi-square test statistics 31.9376 is greater than the chi-square critical value 7.8147, so NULL HYPOTHESIS IS REJECTED at 5% significance.

There is sufficient evidence to warrant rejection of the claim that the distribution of the sample agrees with the distribution of the state populations.

3 0

3 years ago

What proves m ∆ADB and ∆ADC are congruent.

AURORKA [14]

Answer: They're the same angles/measurements.

Step-by-step explanation: Look closely at both the angles. If you measure them, they will be the same because both angles look the same, but ΔADC's side is flipped.

Let me know if you have any questions.

~ Lily, from Brainly.

6 0

3 years ago

An investigator wants to assess whether the mean m = the weight of passengers flying on small planes exceeds the FAA guideline o

stira [4]

Answer:

$H_{0}: \mu= 185$ and $H_{a}: \mu > 185$

Step-by-step explanation:

The null hypothesis $H_{0}$ states that a population parameter (such as the mean, the standard deviation, and so on) is equal to a hypothesized value. We can write the null hypothesis in the form $H_{0}: parameter = value$

In this context, the investigator's null hypothesis should be that the average total weight is no different than the reported value by the FAA. We can write it in this form $H_{0}: \mu= 185$ .

The alternative hypothesis $H_{a}$ states that a population parameter is smaller, greater, or different than the hypothesized value in the null hypothesis. We can write the alternative hypothesis in one of three forms

$H_{a}: parameter > value\\H_{a}: parameter < value\\H_{a}: parameter \neq value$

The investigator wants to know if the average weight of passengers flying on small planes exceeds the FAA guideline of the average total weight of 185 pounds. He should use $H_{a}: \mu > 185$ as his alternative hypothesis.

7 0

3 years ago