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Oliga [24]
3 years ago
6

the total length of 4 blue banners an 5 yellow banners is 49 meters. the total length of 2 blue banners an 1 yellow banner is 17

meters. find the length of the blue banner
Mathematics
2 answers:
marin [14]3 years ago
8 0
Yellow banner is 5
Blue banner is 6
laila [671]3 years ago
3 0
The Yellow-5
The Blue-6
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3 regions are defined in the figure find the volume generated by rotating the given region about the specific line
anastassius [24]

The volume generated by rotating the given region R_{3} about OC is \frac{4}{g}  \pi

<h3>Washer method</h3>

Because the given region (R_{3}) has a look like a washer, we will apply the washer method to find the volume generated by rotating the given region about the specific line.

solution

We first find the value of x and y

y=2(x)^{\frac{1}{4} }

x=(\frac{y}{2} )^{4}

y=2x

x=\frac{y}{2}

\int\limits^a_b {\pi } \, (R_{o^{2} }  - R_{i^{2} } )       dy

R_{o} = x = \frac{y}{2}

R_{i} = x= (\frac{y}{2}) ^{4}

a=0, b=2

v= \int\limits^2_o {\pi } \, [(\frac{y}{2})^{2} - ((\frac{y}{2}) ^{4} )^{2} )  dy

v= \pi \int\limits^2_o= [\frac{y^{2} }{4} - \frac{y^{8} }{2^{8} }}  ] dy

v= \pi [\int\limits^2_o {\frac{y^{2} }{4} } \, dy - \int\limits^2_o {\frac{y}{2^{8} } ^{8} } \, dy ]

v=\pi [\frac{1}{4} \frac{y^{3} }{3}  \int\limits^2_0 - \frac{1}{2^{8} }  \frac{y^{g} }{g} \int\limits^2_o\\v= \pi [\frac{1}{12} (2^{3} -0)-\frac{1}{2^{8}*9 } (2^{g} -0)]\\v= \pi [\frac{2}{3} -\frac{2}{g} ]\\v= \frac{4}{g} \pi

A similar question about finding the volume generated by a given region is answered here: brainly.com/question/3455095

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Identify whether the following
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It opens downwards so it looks like this “n”. That is because a in the formula is a negative number in this situation
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100 POINTS 10 QUESTIONS PLEASE HELP PICTURES BELOW PLEASE SPECIFY WHICH QUESTION YOU ARE ANSWERING
Semenov [28]

Answer:

The answers are \frac{2}{5}, \frac{1}{4}, \frac{1}{10}, \frac{5}{2}, \frac{5}{8}, \frac{4}{1}, \frac{8}{5}, and \frac{10}{1}.

Step-by-step explanation:

Proportions are fractions that can be made by using the given numbers, which in this case are 2, 5, 8, and 20. Let's pair each one with the other three and then simplify if possible.

First, let's begin with 2:

\frac{2}{5} = \frac{2}{5}

\frac{2}{8} = \frac{1}{4}

\frac{2}{20} = \frac{1}{10}

Then, let's do 5:

\frac{5}{2} = \frac{5}{2}

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Now, let us do 8:

\frac{8}{2} = \frac{4}{1}

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\frac{8}{20} = \frac{2}{5}

See how we already have \frac{2}{5}, so we won't have to include that as well.

Finally, let's do 20:

\frac{20}{2} = \frac{10}{1}

\frac{20}{5} = \frac{4}{1}

\frac{20}{8} = \frac{5}{2}

Now see that we already have both \frac{4}{1} and \frac{5}{2}, so we won't have to include both of them, as they are both extras.

Hence, the answers are \frac{2}{5}, \frac{1}{4}, \frac{1}{10}, \frac{5}{2}, \frac{5}{8}, \frac{4}{1}, \frac{8}{5}, and \frac{10}{1}.

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
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Use order of operations for this

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