Can someone with this question pls

Select the three ratios that describe the model.

r-ruslan [8.4K]

Answer:

the ratio of apples to oranges is 4 to 3

3 0

3 years ago

Which expression represents the product of negative three-fourths x and –8x? negative 35 over 4 x 6x negative 35 over 4 x square

valentinak56 [21]

The expression that represents the product of negative three-fourths x and –8x is 6x^2

<h3>How to determine the equivalent expression?</h3>

The statement is given as:

the product of negative three-fourths x and –8x

Rewrite properly as:

-3x/4 * -8x

Divide 4 and 8 by 4

-3x * -2x

Multiply -3 and -2

6x * x

Multiply x and x

6x^2

Hence, the expression that represents the product of negative three-fourths x and –8x is 6x^2

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6 0

2 years ago

I don't understand how this would work. Ive tried to figure it out but i don't know.

barxatty [35]

A. Not sure !! .....l.......

8 0

2 years ago

WHO CAN solve it Please !

Mariulka [41]

Answer:

a) True

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha =0$

Step-by-step explanation:

Step(i):-

Given that the definite integration

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha$

we know that the trigonometric formula

sin²∝+cos²∝ = 1

cos²∝ = 1-sin²∝

step(ii):-

Now the integration

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha = \int\limits^\pi _0 {(\sqrt{cos^{2} \alpha } } \, )d\alpha$

= $\int\limits^\pi _0 {cos\alpha } \, dx$

Now, Integrating

$= ( sin\alpha )_{0} ^{\pi }$

= sin π - sin 0

= 0-0

= 0

Final answer:-

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha =0$

5 0

2 years ago

A sample of carbon dioxide occupies a volume of 3.50 l at 125 kpa pressure. what pressure would the gas exert if the volume was

Novosadov [1.4K]

The gas exerts a pressure of 218.75 kPa when its volume is reduced to 2.0 L, following the behavior of an ideal gas.

Ideal gas behavior:

Suppose the initial volume of carbon dioxide gas is V = 3.5l

Initial pressure is P = 125 kPa

Since the volume is reduced to 2.0l, the final volume is shown as V'= Will be done. 2L

The final pressure of the gas is P'.

We consider the behavior of gas to be ideal. From the ideal gas equation, it becomes as follows.

PV = P'V'

125 × 3.5 = P'× 2

P'= 218.75 kPa

Therefore, the final pressure is 218.5 kPa.

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3 0

1 year ago