if a clock shows it is 3 o'clock, how could you describe the smaller angle made by the two hands of the clock? Solve this proble
2 answers:
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solve for the indicated variable means isolate that variable.
Ans(7)
P=IRT (T)
that means solve for T or make T alone on one side of equal.
To do that we just need to move IR on the left side
So we get:
Hence final answer will be
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Ans(8)
2x-3y=8 (y)
-3y=8-2x
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Ans(9)
V=LWH (L)
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Ans(10)
A=2(L+W) (w)
A=2L+2W
A-2L=2W
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Ans(11)
ax+by=c (y)
by=c-ax
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Ans(12)
(R)
PN=R-C
PN+C=R
R=PN+C
First exercise:
a. The first prime numbers are 2,3,5,7,11,... So, the greatest prime interger between 4 and 9 is 7. A = 7.
b. Since the number line's growing direction is rightwards, going to the left means to decrease. So, point E is 4 less than point A, i.e. 7-4 = 3. E = 3.
c. The additive inverse of a number is another number
such that
. So, we're looking form a number such that
, and thus O = - 3.
d. This point looks a bit ambiguous to me honestly. We know that IO = 2, which I presume means that the points I and O are two units apart, but we're not told if I is two units left or right with respect to O. To solve this issue, I'm assuming that IO implies that I sits before O, and so I is two units left with respect to O. As we said in point a., two units left means two less, so we have I = -3-2 = -5. At this point, point L is halfway between -5 and -3, and thus L = - 4.
e. The sum of the coordinates of A and E is 7 + 3 = 10. Half that sum is 5, so M = 5.
In the attached image, you can see the number line filled with the points asked by the exercise.
Second exercise:
All the requests can be written as an equation in which we look for the values of x. Below you find the equation and the solutions.
A little side note: I've honestly never met the expression "subtract A to B", but always "subtract A from B". I assumed they mean the same thing, but if anybody thinks I'm wrong please let me know! (I'm not a native speaker, so I can only refer to the math I met during my studies).
