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Feliz [49]
3 years ago
7

A chemical company makes two brands of antifreeze. The first brand is 40% pure antifreeze, and the second brand is 60% pure anti

freeze. In order to obtain 180 gallons of a mixture that contains 55% pure antifreeze, how many gallons of each brand of antifreeze must be used?
First brand =
Second Brand=
Mathematics
1 answer:
Semenov [28]3 years ago
4 0

Answer:

Step-by-step explanation:

Let x be the portion of 60%

180 - x is the portion of 40%

0.60x + 0.40(180 - x) = 0.55(180)

0.60x + 72 - 0.40x = 99

0.20x = 27

x = 135

180 - 135 = 45

First brand = 45 gallons of 40%

Second Brand = 135 gallons of 60%

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Answer:

(x+4)^2+(y+6)^2=100

Step-by-step explanation:

Given a circle centred at the point P(-4,-6) and passing through the point

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\text{Distance Formula=}\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\text{Radius=}\sqrt{(2-(-4))^2+(2-(-6))^2} \\=\sqrt{(2+4))^2+(2+6)^2}\\=\sqrt{6^2+8^2}\\=\sqrt{100}\\Radius=10

Step 2: Determine the equation

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(x-(-4))^2+(y-(-6))^2=10^2\\\\(x+4)^2+(y+6)^2=100

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3 years ago
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murzikaleks [220]

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5 0
2 years ago
Given that f(x) = 2x + 1 and g(x) = −5x + 2, solve for f(g(x)) when x = 3.
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