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2 years ago

Tell whether the angles are adjacent or vertical. Then find the value of $x$ .

Mathematics

1 answer:

boyakko [2]2 years ago

7 0

Answer:

they are adjacent angles

Step-by-step explanation:

for adjacent angles

${(x + 3)}^{o} = {84}^{0} \\ x = 84 - 3 \\ x = 81$

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Which trigonometric ratios are correct for triangle ABC? Check all that apply

sergij07 [2.7K]

Consider an angle M with measure m≠90°, in a right triangle.

Let

OPP denote the length of the side opposite to M,
ADJ denote the length of the side adjacent to M, and
HYP denote the hypotenuse.

then:

Sin(M) = OPP/HYP
Cos(M)= ADJ/HYPP
Tan(M)=OPP/ADJ

Back to our problem,

using the Pythagorean we can find the length of AB:

$|AB|^2+|AC|^2=|BC|^2\\\\|AB|^2+9^2=18^2\\\\|AB|^2=18^2-9^2\\\\|AB|^2=(18-9)(18+9)=9 \cdot 27=9 \cdot 9 \cdot3\\\\|AB|=9 \sqrt{3} 
$

$Sin(C)= \frac{OPP}{HYP}=\frac{9 \sqrt{3} }{18}= \frac{ \sqrt{3} }{2}$
$Cos(B)= \frac{ADJ}{HYP}= \frac{9 \sqrt{3}}{18}= \frac{ \sqrt{3}}{2}$
$Tan(C)= \frac{OPP}{ADJ}= \frac{9 \sqrt{3} }{9}= \sqrt{3}$
$Sin(B)= \frac{OPP}{HYP}= \frac{9}{18}= \frac{1}{2}$
$Tan(B)= \frac{OPP}{ADJ}= \frac{9}{9 \sqrt{3}}= \frac{1}{ \sqrt{3} }= \frac{ \sqrt{3}}{3}$

Answer: 1, 3, 4

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3 years ago

A regulation basketball hoop has a rim with an 18-inch diameter. What is the approximate length around the rim of a regulation b

pogonyaev

Answer:

Step-by-step explanation:

4 0

4 years ago

2x^2(x^2) what’s the product of this

Snezhnost [94]

2x^4(or 2x to the fourth power

6 0

2 years ago

What is the slope intercept of 2y=14-4x

pentagon [3]

7, 14 would be it but you have to divide the whole equation by 2 to get the y alone

4 0

3 years ago

Read 2 more answers

There are no results for The impedance Z in an AC (alternating current) circuit is a measure of how much the circuit impedes (hi

Semmy [17]

Answer:

Step-by-step explanation:

If the impedance is related to the voltage and the current by the formula V = IZ where;

V is the voltage

I is the current

Z is the impedance

Given

I = 0.4+3i

V = 0.3-2i

Voltage V = (0.4+3i)(0.3-2i)

V = 0.4(0.3)-0.8i+0.9i-6i²

V = 0.12+0.1i -6i²

Since i² = -1

V = 0.12+0.1i-6(-1)

V = 0.12+0.1i+6

V = 6.12+0.1i.

Hence the impedance is 6.12+0.1i

7 0

3 years ago