The first step in the process for factoring the trinomial x^2-4x-32 is to:

Please answer this question based on the following data. SSTR = 6,750 H0: μ1= μ2=μ3=μ4 SSE = 8,000 Ha: at least one mean is diff

Nookie1986 [14]

Answer:

$P_v =P(F_{3,16}>4.5)=0.0180$

So on this case the best option for the answer would be:

between .01 and .025

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

If we assume that we have $4$ groups and on each group from $j=1,\dots,5$ we have $5$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between=Treatment}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2 =6750$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2 =8000$

And we have this property

$SST=SS_{between}+SS_{within}=6750+8000=14750$

The degrees of freedom for the numerator on this case is given by $df_{num}=k-1=4-1=3$ where k =4 represent the number of groups.

The degrees of freedom for the denominator on this case is given by $df_{den}=df_{between}=N-K=20-4=16$ .

And the total degrees of freedom would be $df=N-1=20 -1 =19$

We can find the $MSR=\frac{6750}{3}=2250$

And $MSE=\frac{8000}{16}=500$

And the we can find the F statistic $F=\frac{MSR}{MSE}=\frac{2250}{500}=4.5$

And with that we can find the p value. On this case the correct answer would be 3 for the numerator and 16 for the denominator.

$P_v =P(F_{3,16}>4.5)=0.0180$

So on this case the best option for the answer would be:

between .01 and .025

6 0

4 years ago

A highway contractor owns heavy equipment which is used during the warm weather. During the winter months the equipment is to be

Kipish [7]

Answer:

a) 0.04

b) The choice of renting a protected area should be made

c) Indifference probability, P = 0.25

Step-by-step explanation:

a) Probability that the 25-year flood takes place in a given year.

This means that the flood is taking place once in 25 years, and the probability that it takes place in this given year is 1/25 = 0.04

b) The contractor is left with two alternatives, either to stay in protected area or flood plain area.

We will calculate the cost of staying in protected area and the loss incurred if he stays in the flood plain area. The one with the lesser value will be the more preferred decision.

Probability of a damaging flood, pr (flood) = 0.02

Probability of high damage if he chooses the flood plain = 0.5

Pr(high damage) = 0.02 * 0.5 = 0.01

Probability of low damage if he chooses the flood plain = 0.5

Pr(low damage) = 0.02 * 0.5 = 0.01

Loss(low damage) = $400,000

Loss(High damage) = %600,000

Average loss = [Pr(low damage)*Loss(low damage)] + [Pr(high damage) *Loss(High damage) ]

Average loss = (400000*0.01) + (600000*0.1)

Average loss = 4000 + 6000

Average loss = $10,000

Winter lasts for three months, i.e number of months = 3

Therefore the costs of renting the areas should be charged per month

Cost of renting flood plain = $10000 per year = 10000/12 = $833.22/month

Cost of renting protected area = $35000 per month = 35000/12 = $2916.67/month

The protected area is not used

Cost of rent for 1 month = $2916.67 - $833.22

Cost of rent for 1 month = $2083.45

Cost of renting protected area in 3 months = 3 * 2083.45 = $6250.34

Since the cost of renting protected area is less than the loss incurred in flood plain area, the contractor should rent a protected area

c)The principle of indifference states that in the absence of any relevant evidence, agents should distribute their credence equally among all the possible outcomes under consideration.

The probability of high or low damage = 0.50

Since there are just two options, and indifference does not assign probabilities based on prior information

Probability(flood) = 0.5

Probability that a flood with high damage will occur = Probability (flood) * Pr(high damage) = 0.5 * 0.5 = 0.25

Probability that a flood with low damage will occur = Probability (flood) * Pr(low damage) = 0.5 * 0.5 = 0.25

3 0

3 years ago

Mrs. Pate’s class all got A’s on their math test, so she bought chocolate bars as a reward the next day. During the night,howeve

Galina-37 [17]

4 students:3 bars=3/4 bar per person
3/4 bar x 4 students=3 whole bars
☺☺☺☺

5 0

4 years ago