Question

The measure of one angle of a right triangle is 50 more than the measure of the smallest angle. Find the measures of all three angles. Enter the angles from smallest to largest.

Answer 1

Answer:

$1.76^{0}$, $88.24^{0}$  and  $90^{0}$

Step-by-step explanation:

Since the triangle is a right angled triangle, one of its angles is $90^{0}$.

To determine the degrees of other angles, let the smallest angle be represented by y. Thus, the third angle is 50y.

So that:

$y^{0}$ + 50$y^{0}$  + $90^{0}$ = $180^{0}$

51$y^{0}$ = $180^{0}$ -  $90^{0}$

51$y^{0}$ =  $90^{0}$

$y^{0}$ = $1.7647^{0}$

$y^{0}$ ≅ $1.76^{0}$

Therefore,

50$y^{0}$ = 50 x 1.76471

        = $88.2355^{0}$

        ≅ $88.24^{0}$

The angles of the triangle are: $1.76^{0}$, $88.24^{0}$  and  $90^{0}$.