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stiv31 [10]
3 years ago
11

Help!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Andru [333]3 years ago
7 0

Step-by-step explanation:

The area would be 9 times compared to the area of the original square. To test this, you can let the side of the original square be equal 1. By tripling this side, the side becomes three. Utilizing the area of a square formula, A= s^2, the area of the original square would be 1 after substituting 1 for s. Then, you do the same for the area of the tripled square. With the substitution, the area of the tripled square would be 9. This result displays the area of the tripled square being 9 times as large as the area of the original square. This pattern can be used for other measurements of the square such as:

let s = 2, Original Area= 2^2 = 4 Tripled Area= (2(3))^2 = 6^2= 36. 36/4 = 9

let s = 3, Original Area = 3^2 = 9 Tripled Area - (3(3))^2 = 9^2 =81. 81/9 = 9

let s = 4, Original Area = 4^2 = 16 Tripled Area - (4(3))^2 = 12^2 = 144. 144/16 = 9

let s = 5, Original Area = 5^2 = 25 Tripled Area - (5(3))^2 = 15^2 = 225. 225/25 = 9

let s = 6, Original Area = 6^2 = 36 Tripled Area - (6(3))^2 = 18^2 = 324. 324/36 = 9

let s = 7, Original Area = 7^2 = 49 Tripled Area - (7(3))^2 = 21^2 = 2,401. 2,401/49 = 9

You can continue to increase the length of the square and follow this pattern and it will be consistent.

AlladinOne [14]3 years ago
6 0

answer is 9

The area would be 9 times compared to the area of the original square. To test this, you can let the side of the original square be equal 1. By tripling this side, the side becomes three. Utilizing the area of a square formula, A= s^2, the area of the original square would be 1 after substituting 1 for s. Then, you do the same for the area of the tripled square. With the substitution, the area of the tripled square would be 9. This result displays the area of the tripled square being 9 times as large as the area of the original square. This pattern can be used for other measurements of the square such as:

let s = 2, Original Area= 2^2 = 4 Tripled Area= (2(3))^2 = 6^2= 36. 36/4 = 9

let s = 3, Original Area = 3^2 = 9 Tripled Area - (3(3))^2 = 9^2 =81. 81/9 = 9

let s = 4, Original Area = 4^2 = 16 Tripled Area - (4(3))^2 = 12^2 = 144. 144/16 = 9

let s = 5, Original Area = 5^2 = 25 Tripled Area - (5(3))^2 = 15^2 = 225. 225/25 = 9

let s = 6, Original Area = 6^2 = 36 Tripled Area - (6(3))^2 = 18^2 = 324. 324/36 = 9

let s = 7, Original Area = 7^2 = 49 Tripled Area - (7(3))^2 = 21^2 = 2,401. 2,401/49 = 9

You can continue to increase the length of the square and follow this pattern and it will be consistent.

How many perfect squares are there between 1,000,000 and 9,000,000?

2,802 Views

If the side of the square is triple, how many times will its area be as compared to the area of the original shape?

1,347 Views

Consider a square whose side is 1 unit. If the measure of its side is doubled, what will be its new area as compare to the smaller square? How about if the side of the smaller square was tripled, what will be its new area?

1,863 Views

If each side of a square was increased by 3 cm, the area would be 4 times that of the original square. What is the length of the side of the originally square?

1,702 Views

If the side of a square is tripled, how many times the perimeter of the first square will that of the new square be?

If the side of a square is tripped how many times will it area be, as compared to the area of the original square?

If the side of a square is tripled then the area would be increased 9 times assuming the goal is to keep the shape a square. Meaning if one side is tripled then all sides are tripled and all corners remain 90 degrees. X being the original length, then 3x is the tripled length. The area of a square is base times height. Where all sides are the same then the area of a square is x squared. Kinda how that term came about. So tripling one side triples all sides. So x times thee times x times three . So x squared times nine is the area of a square who’s side

If the side of a square is tripled, how many times will it’s area be as compared to the area of the original square?

Your question is a little tricky because of the phrase “the side”. Saying “the” side makes it sound like the square has only one when it really has four. It makes it a little difficult to divine your intent, i.e. did you intend for just one side to be tripled in which case the resulting figure would be a rectangle or did you intend for the final figure to still be a square in which case both dimensions would have to be tripled?

In the former case, the area would change by just a factor of 3. In the later, it would change by a factor of 9 as others have

x = square side

x^2 = original area

(3x)^2 = area of square with tripled sides

(3x)^2 / x^2 = 9 - divide the new area with the original one to see how many times larger it is.

The area will be nine times larger.

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An object is heated to 100°. It is left to cool in a room that
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Answer:

Step-by-step explanation:

Use Newton's Law of Cooling for this one.  It involves natural logs and being able to solve equations that require natural logs.  The formula is as follows:

T(t)=T_{1}+(T_{0}-T_{1})e^{kt} where

T(t) is the temp at time t

T₁ is the enviornmental temp

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k is the cooling constant which is different for everything, and

t is the time (here, it's in minutes)

If we are looking first for the temp after 20 minutes, we have to solve for the k value.  That's what we will do first, given the info that we have:

T(t) = 80

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Filling in to solve for k:

80=30+(100-30)e^{5k} which simplifies to

50=70e^{5k} Divide both sides by 70 to get

\frac{50}{70}=e^{5k} and take the natural log of both sides:

ln(\frac{5}{7})=ln(e^{5k})

Since you're learning logs, I'm assuming that you know that a natural log and Euler's number, e, "undo" each other (just like taking the square root of something squared).  That gives us:

-.3364722366=5k

Divide both sides by 5 to get that

k = -.0672944473

Now that we have a value for k, we can sub that in to solve for T(20):

T(20)=30+(100-30)e^{-.0672944473(20)} which simplifies to

T(20)=30+70e^{-1.345888946}

On your calculator, raise e to that power and multiply that number by 70:

T(20)= 30 + 70(.260308205) and

T(20) = 30 + 18.22157435 so

T(20) = 48.2°

Now we can use that k value to find out when (time) the temp of the object cools to 35°:

T(t) = 35

T₁ = 30

T₀ = 100

k = -.0672944473

t = ?

35=30+100-30)e^{-.0672944473t} which simplifies to

5=70e^{-.0672944473t}

Now divide both sides by 70 and take the natural log of both sides:

ln(\frac{5}{70})=ln(e^{-.0672944473t}) which simplifies to

-2.63905733 = -.0672944473t

Divide to get

t = 39.2 minutes

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Find the area of the following circles. a. A circle with a 8-inch radius b. A circle with a 10-kilometer radius c. A circle with
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Area of a circle is A= \pi r^2.  The first one, a, the radius squared is 8*8=64.  So A=64 \pi.  If you multiply in pi as 3.14, you'll have 200.96 square inches.  The second one, b, the radius squared is 10*10=100.  So A=100 \pi square kilometers.  If you multiply in pi as 3.14 you'll have 314 square kilometers.  The third one, c, the radius squared is 14*14=196.  So A=196 \pi yd^2.  Or you could multiply in pi as 3.14 to get 615.44 yd squared.  For the last one, d, the radius squared is 22*22=484 cm.  Therefore, A=484 \pi cm^2, or multiply in 3.14 for pi to get 1519.76 cm squared.  There you go!
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3 years ago
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GREYUIT [131]

Answer:

second option, IQR = 13-6 = 7 and Range = 17-6 = 11

Step-by-step explanation:

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2 years ago
A 35 foot rope is cut into two pieces with one section 6 times as long as the other section, how is the shorter piece?
guajiro [1.7K]
-------------------------------------------
Define x:
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Let the shorter piece be x.
Shorter piece = x
Longer piece = 6x

-------------------------------------------
Construct equation:
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x +6x =35
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-------------------------------------------
Find the length:
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Shorter length = x = 5 feet
Larger length = 6x = 6(5) = 30 feet

-------------------------------------------
Answer: The shorter piece is 5 feet.
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