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Nadusha1986 [10]
1 year ago
10

What is the Volume of the square pyramid? (Round to the nearest tenth as needed)

Mathematics
2 answers:
GrogVix [38]1 year ago
8 0
<h3><u>given</u><u>:</u></h3>

base= 25mm

height= 28mm

<h3><u>to</u><u> </u><u>find</u><u>:</u></h3>

the volume of the pyramid.

<h3><u>solution</u><u>:</u></h3>

v= a^2 h/3

v= 25^2 28/3

v= 5833.33333

v= 5833.3mm^3

Nadya [2.5K]1 year ago
7 0
<h3><u>let's</u><u> </u><u>solve</u><u>:</u></h3>

v =  {a}^{2}  \times  \frac{h}{3}

v =  {25}^{2}  \times  \frac{28}{3}

v = 5833.33333

nearest \: tenth = 5833.3 {mm}^{3}

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Given the figure below, find the values of x and z.
iragen [17]

Answer:

x=6 and z=107

Step-by-step explanation:

From the figure or diagram we can say that

z+15x-17=180 ---(1)

z+11x+7=180 ---(2)

Subtracting (1) and (2)

z+15x-17-(z+11x+7)=180-180

4x-24=0

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Substitute x=6 in (2)

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In any cyclic quadrilateral, angles opposite one another are supplementary, meaning

m\angle K+m\angle I=m\angle L+m\angle J=180^\circ

and given that \boxed{m\angle K=64^\circ}, we have \boxed{m\angle I=116^\circ}.

By the inscribed angle theorem,

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m\angle ILJ=\dfrac12m\widehat{IJ}

and since

m\angle L=m\angle JLK+m\angle ILJ

we have

m\angle L=\dfrac{97^\circ+59^\circ}2\implies\boxed{m\angle L=78^\circ}

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PLEASE ITS DO TOMORROW
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Here you go :) !!!!!!!!

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alisha [4.7K]

Answer:

1 kilometre =

100000 centimetres

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