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Nonamiya [84]
3 years ago
10

When calculating for volume, you use the area of the 2D shape. True or false.

Mathematics
2 answers:
bixtya [17]3 years ago
8 0

false false false false false

Nana76 [90]3 years ago
5 0

Answer:

I think true.

Step-by-step explanation:

Whereas the basic formula for the area of a rectangular shape is length × width, the basic formula for volume is length × width × height.

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Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, -1).
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Line:
3x+y=7
y=-3x+7

Slope of Perpendicular Line: 1/3x

For the perpendicular line to contain point (6,-1) the y-intercept would be (0,1), thus the equation of the line would be y=1/3x+1

y=1/3x+1

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What are the prime factors of 63 in ascending order
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What is the solution to the following system of equations?
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Joel’s veterinarian tells him that he can give his dog 11 5/8 mg of Benadryl for relief of his dogs allergies. Joel’s dog weighs
Sav [38]

Step-by-step explanation:

Given that,

The dosage of Benadryl for Dog is 11\dfrac{5}{8}\ mg

Weight of Joel's Dog is 15\dfrac{1}{2}\ \text{pounds}

(a)  Benadryl dosage per pound for Joel’s dog is calculated as :

\dfrac{11\dfrac{5}{8}}{15\dfrac{1}{2}}=\dfrac{\dfrac{11\times 8+5}{8}}{\dfrac{15\times 2+1}{2}}\\\\=\dfrac{\dfrac{93}{8}}{\dfrac{31}{2}}\\\\=\dfrac{93}{8}\times \dfrac{2}{31}\\\\=0.75\ \text{dosage per pound}

(b) If the weight of the Dog is 12 pounds, it means

\dfrac{11\dfrac{5}{8}}{12}\ \text{dosage per pounds}\\\\=\dfrac{\dfrac{93}{8}}{12}\\\\=\dfrac{93}{8}\times \dfrac{1}{12}\\\\=0.968\ \text{dosage per pounds}

Therefore, this is the required solution.

3 0
2 years ago
The scores on a psychology exam were normally distributed with a mean of 57
olya-2409 [2.1K]

Answer:

Cutoff for a failing score is 49 and 2.28% students failed.

Step-by-step explanation:

We have been given that scores on a psychology exam were normally distributed with a mean of 57  and a standard deviation of 4.

2 standard deviation below mean would be,

57-2(4) =57-8= 49

Therefore,Cutoff far a failing score is 49.

Now let us find out the z-score for our given values,

z=\frac{x-\mu}{\sigma}

z=\frac{49-57}{4}=\frac{-8}{4} =-2

Now let us look up the probability from normal distribution table.

P(z

Therefore, percentage of students failed is 2.28%.



3 0
3 years ago
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