Answer:
A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
That is z with a pvalue of
, so Z = 1.645.
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.


The lower end of the interval is the sample mean subtracted by M. So it is 34.09 - 3.25 = 30.84.
The upper end of the interval is the sample mean added to M. So it is 34.09 + 3.25 = 37.34.
A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).
Answer:
The result is 19
Step-by-step explanation:

Step 1: Parenthesizing (5-2)=3

Step 2: Exponentiation 

Step 3: Multiplication and division 3x4=12 and 6/3=2

Step 4: Addition and subtraction 9+12=21, and 21-2=19
21-2
19
The operations are ordered from highest to lowest in the order:
1. Parenthesizing,
2. Factorial,
3. Exponentiation,
4. Multiplication and division,
5. Addition and subtraction.
Hope this helps!
Answer:
False
Step-by-step explanation:
Well to solve for z we single it out, distribute, use the communicative property, and combine like terms.
42 = -7(z - 3)42 = -7(z - 3)
Distribute
42 = -7z + 21*42 = -7z + 21
42 = -7z + 882 = -7z + 21
-42 to both sides
-7z + 840 = -7z + 21
-21 to both sides
-7z + 819 = -7z
+7z to both sides
819 = 0
<em>Thus, </em>
<em>the given equation is false.</em>
<em>I hope this helps :)</em>
Answer:
87.47 cm
Step-by-step explanation:
112-24.53 is 87.47