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Alina [70]
3 years ago
5

Solve for x. -3/5x = 15 A. -25 B. -9 C. -6 D. 9

Mathematics
2 answers:
CaHeK987 [17]3 years ago
6 0

Answer: If the question is formed as (- 3/5) x = 15

then A is correct

X=-25

Step-by-step explanation:

vitfil [10]3 years ago
3 0

wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink  wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink wink

You might be interested in
2/7 divided by 1/2 as a mixed number
Readme [11.4K]

Answer:

4/7

Step-by-step explanation:

2/7 ÷1/2=2/7 × 2 = 4/7

Hope this helps :D

8 0
3 years ago
Why does an enzyme function as a catalyst in a reaction?
Katyanochek1 [597]
I believe the answer would be B. Catalysts lower the activation energy. 
4 0
3 years ago
5y-5y^2-5+2+2y+3y^2-1
LiRa [457]
5y-5y^2-5+2+2y+3y^2-1

collect like terms

7y-2y^2-4

reorder the terms

-2y^2+7y-4

-2y^2+7y-4 is your final answer, I hope this helps!
6 0
3 years ago
Read 2 more answers
How to solve for shaded area
tamaranim1 [39]

Answer:

(a)  12.96 ft²

(b)  21.5 in²

Step-by-step explanation:

(a) For the first diagram

Area of the shaded region (A) = Area of Tripezium- area of circle

A = [1/2(a+b)h]-[πr²]............... Equation 1

Where a and b are the parallel side of the tripezium respectively, h = height of the tripezium, r = radius of the circle.

From the diagram,

Given: a = 15 ft, b = 6 ft, h = 12 ft, r = h/2 = 12/2 = 6 ft.

Constant: π = 3.14

Substitute these values into equation 1

A = [12(15+6)/2]-(3.14×6²)

A = 126-113.04

A = 12.96 ft²

(b) For the second diagram,

Area of the shaded region (A') = Area of square- area of circle

A' = (L²)-(πr²)............. Equation 2

Where L = lenght of one side of the square, r = radius of the circle

From the diagram,

Given: L = 2r = (2×5) = 10 in, r = 5 in

Substitute these values into equation 2

A' = (10²)-(3.14×5²)

A' = 100-78.5

A = 21.5 in²

5 0
3 years ago
Determine if the equation is linear. If so, graph the function.
Alexeev081 [22]

Answer:

I don't know I'm just answering questions because i need points

Step-by-step explanation:

ehh can I get a brainless?

6 0
3 years ago
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