3 years ago

What is the area of a pentagon using the side length of 4

1 answer:

3 0

In this equation, n = # of sides
Area = n * (side length)² / 4*tan (180 / n)
Area = 5 * 4² / 4 * tan (36)
Area = 80 / 4 * 0.72654
Area = 80 / 2.90616 
Area = 27.5277341922 

 Source:
http://www.1728.org/polygon.htm

You might be interested in

If the aspect ratio of a chalkboard is 8:6 and the width is 9in, what is the length of the eraser?

KIM [24]

I believe it's A. Sometimes you have to take an educated guess.

6 0

3 years ago

Find the volume of the cylinder. Use pi = 3.14* the height of 6 inches and a radius 4.5in

ArbitrLikvidat [17]

Answer: 381.51 cubic inches

Step-by-step explanation:

1. Use the formula: V = π $r^{2}$ h, or in this case, 3.14( $4.5^{2}$ )(6)

2. Simplify to 3.14(20.25)(6)

3. Simply multiply all three numbers using a calculator, or one by one if that's the preferred option.

4. You get: 381.51 cubic inches.

8 0

3 years ago

Can u solve it plz thx

Harman [31]

The answer is 77 becuase you have to add all of the sides that are same as the number

6 0

2 years ago

Read 2 more answers

10 more than a number divided by -8

Effectus [21]

Answer:

6X8=48 10 more is 58

Step-by-step explanation:

6 0

2 years ago

Find the area of the shaded region. pls do this with explanation.

vladimir1956 [14]

Answer:

first find the area of the big rectangle = 12×14=168

area of the small unshaded rectangle =2×5×6=60

area of the shaded region = 168-60=108

6 0

2 years ago

Read 2 more answers