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2 years ago

(x+3)(3x² - 5x - 10) multiply polynomial

Mathematics

2 answers:

zmey [24]2 years ago

8 0

Answer:

$3x^2 + 4x^2 - 25x - 30$

Step-by-step explanation:

Step 1: Distribute

$(x + 3)(3x^2 - 5x - 10)$

$(x * 3x^2) + (x * (-5x)) + (x * (-10)) + (3 * 3x^2) + (3 * (-5x)) + (3 * (-10))$

$3x^3 - 5x^2 - 10x + 9x^2 - 15x - 30$

Step 2: Combine like terms

$3x^3 - 5x^2 + 9x^2 - 15x - 10x - 30$

$(3x^2) + (-5x^2 + 9x^2) + (-15x - 10x) + (-30)$

$3x^2 + 4x^2 - 25x - 30$

Answer: $3x^2 + 4x^2 - 25x - 30$

brilliants [131]2 years ago

6 0

Answer:

$\boxed{\sf{3x^3+4x^2-25x-30}}$

Step-by-step explanation:

$\underline{\text{SOLUTION:}}$

To isolate the term of x from one side of the equation, you must multiply by a polynomial.

$\underline{\text{GIVEN:}}$

$:\Longrightarrow: \sf{(x+3)(3x^2 - 5x - 10)}$

You have to solve with parentheses first.

$:\Longrightarrow \sf{x\cdot \:3x^2+x\left(-5x\right)+x\left(-10\right)+3\cdot \:3x^2+3\left(-5x\right)+3\left(-10\right)}$

Solve.

$\sf{x*3x=3x^3}$

x(-5x)=-5x²

$\sf{x(-10)=-10x}$

3*3x²=9x²

3(-5x)=-15x

3(-10)=-30

Then, rewrite the problem down.

$\sf{3x^3-5x^2-10x+9x^2-15x-30}$

Combine like terms.

$\Longrightarrow: \sf{3x^3-5x^2+9x^2-10x-15x-30}$

Add/subtract the numbers from left to right.

-5x²+9x²=4x²

$\Longrightarrow: \sf{3x^3+4x^2-10x-15x-30}$

Solve.

$\sf{-10x-15x=-25x}$

Then rewrite the problem.

$\Longrightarrow: \boxed{\sf{3x^3+4x^2-25x-30}}$

Therefore, the correct answer is 3x³+4x²-25x-30.

I hope this helps! Let me know if you have any questions.

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