The answer to this problem is 45
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<u>Answer:</u></h3>

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<u>Step-by-step explanation:</u></h3>
Given function to us is :-
And we , need to write the function a a product of linear factor by grouping or using the x method or a combination of both . So let's factorise this ,
I have also attached the graph of x²-9.
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<u>Hence </u><u>option</u><u> </u><u>A</u><u> </u><u>is</u><u> </u><u>corr</u><u>ect</u><u> </u><u>.</u></h3>
Hello from MrBillDoesMath!
Answer: (4b-6) log(a) = log (3c + d)
Discussion:
Take the log of both sides of the equation:
log ( a ^(4b-6)) = log (3c + d)
As the log functions causes exponents to become multiplexers, this equation is the same as
(4b-6) log(a) = log (3c + d)
Thank you,
MrB
Answer:
Please check the explanation.
Step-by-step explanation:
<u>Determining equation B from Equation A</u>
Given the equation A

Apply distributive law
which is equation B
Hence, equation B can be obtained by implementing the distributive law operation on equation A.
<u>Determining equation A from Equation B</u>
Given the equation B

Factor out common term -2 on the right-hand side of the equation
which is the equation A
Hence, equation A can be obtained by factoring out the common term -2 on the right-hand side of equation B.