Answer:
it is either positve 13 or negative 13
Step-by-step explanation:
Answer:
proof below
Step-by-step explanation:
Remember that a number is even if it is expressed so n = 2k. It is odd if it is in the form 2k + 1 (k is just an integer)
Let's say we have to odd numbers, 2a + 1, and 2b + 1. We are after the sum of their squares, so we have (2a + 1)^2 + (2b + 1)^2. Now let's expand this;
(2a + 1)^2 + (2b + 1)^2 = 4a^2 + 4a + 4b + 4b^2 + 4b + 2
= 2(2a^2 + 2a + 2b^2 + 2b + 1)
Now the sum in the parenthesis, 2a^2 + 2a + 2b^2 + 2b + 1, is just another integer, which we can pose as k. Remember that 2 times any random integer, either odd or even, is always even. Therefore the sum of the squares of any two odd numbers is always even.
Idk it’s seems idk idk idk
In terms of diameter (d), the area (A) of a circle is given by the formula
A = (π/4)d²
You have d=20 yd, so the area of the circle is
A = (π/4)×(20 yd)² . . . . substitute the given information into the formula
A = 100π yd² . . . . . . . . do the arithmetic
A ≈ 314.16 yd²
Answer:
g(x) has an axis of symmetry at x = 3.
g(x) is shifted right 3 units from the graph of f(x)
g(x) is shifted up 4 units from the graph of f(x).
Step-by-step explanation:
The parent function is:
The transformed function is 
.
This new function can be rewritten in the vertex form as:
This function is obtained by shifting the parent function 3 units right and 4 units up.
The axis of symmetry is x=3;(x=h) and h=3.
There is no horizontal stretch or compression.
The new function is however reflected in the x-axis
