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2 years ago

8

What is the solution to the inequality |2x + 3| < 7? 4 < x < 10 –5 < x < 2 x < 4 or x > 10 x < –5 or x &

gt; 2

1 answer:

pychu [463]2 years ago

3 0

Answer:

4(−10−9x)

Step-by-step explanation:

You might be interested in

M/3-4<-1 <br> answer this question<br> please show your work

Len [333]

Answer:

m<9

Step-by-step explanation:

m/3 - 4 < -1

+4 +4

______________

m/3<3

× 3 ×3

__________

m<9

Hope this Helps!

3 0

2 years ago

Read 2 more answers

HELP PLEASE!!<br><br> Which one is correct? =/ or = ?

Delicious77 [7]

The answer is = since each equation equals 32
6•6=36
2•2=4
36-4=32
And then the next equation
6+2=8
4(8)=32

3 0

1 year ago

Read 2 more answers

When using the order of operations to simplify (7 + 3) * 4 - 1 + (6 + 8), which operation should be performed first?

enot [183]

Answer:

addition because it's in parentheses and following PEMDAS parentheses comes first so you do addition first.

I hope you find this helpful :D

5 0

2 years ago

Read 2 more answers

A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0

2 years ago

Student Debt – Vermont: The average student loan debt of a U.S. college student at the end of 4 years of college is estimated to

mezya [45]

Answer:

The confidence interval is (24116.3878,24883.6122).

Step-by-step explanation:

We are given the following information in the question:

Population mean, $\mu$ = $23,500

Sample mean, $\bar{x}$ = $24,500

Sample standard deviation,s = $2,800

Sample size, n = 146

Confidence interval:

$\bar{x} \pm t_{critical}\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at}~\alpha_{0.05} = \pm 1.655436$

$24500 \pm 1.65543(\frac{2800}{\sqrt{146}} ) = 24500 \pm 383.6122 = (24116.3878,24883.6122)$

The confidence interval is (24116.3878,24883.6122).

5 0

2 years ago