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3 years ago

Lines g, h, and l are parallel and m 2 = 132°.

Mathematics

1 answer:

Sonbull [250]3 years ago

7 0

Answer: It is c

Step-by-step explanation:

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I’ll mark you brainlist I’ll mark you brainlist write in y=mx+b form

Sergio [31]

Y=-2/1x ivigvyvitvtuyvsybsubeeuwub

7 0

3 years ago

Suppose that you were not given the sample mean and sample standard deviation and instead you were given a list of data for the

Troyanec [42]

Answer:

So, the sample mean is 31.3.

So, the sample standard deviation is 6.98.

Step-by-step explanation:

We have a list of data for the speeds (in miles per hour) of the 20 vehicles. So, N=20.

We calculate the sample mean :

$\mu=\frac{19 +19 +22 +24 +25 +27 +28+ 37 +35 +30+ 37+ 36+ 39+ 40+ 43+ 30+ 31+ 36+ 33+ 35}{20}\\\\\mu=\frac{626}{20}\\\\\mu=31.3$

So, the sample mean is 31.3.

We use the formula for a sample standard deviation:

$\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}$

Now, we calculate the sum

$\sum_{i=1}^{20}(x_i-31.3)^2=(19-31.3)^2+(19-31.3)^2+(22-31.3)^2+(24-31.3)^2+(25-31.3)^2+(27-31.3)^2+(28-31.3)^2+(37-31.3)^2+(35-31.3)^2+(30-31.3)^2+(37-31.3)^2+(36-31.3)^2+(39-31.3)^2+(40-31.3)^2+(43-31.3)^2+(30-31.3)^2+(31-31.3)^2+(36-31.3)^2+(33-31.3)^2+(35-31.3)^2\\\\\sum_{i=1}^{20}(x_i-31.3})^2=926.2\\$

Therefore, we get

$\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}\\\\\sigma=\sqrt{\frac{1}{19}\cdot926.2}\\\\\sigma=6.98$

So, the sample standard deviation is 6.98.

3 0

2 years ago

Evaluate the function for x=3a

antoniya [11.8K]

Nothing further can be done with this x=3a

7 0

3 years ago

6 Which equation has a solution of s = 9.5 ? F -5s = -47.5 G -3 + s = 12.5 H --2s 19 J –1 + s = 10.5

earnstyle [38]

Answer:

F. -5s = -47.5

Step-by-step explanation:

F. -5s = -47.5

s = -47.5 / -5

s = 9.5

This is the correct option

G. -3 + s = 12.5

s = 12.5 + 3

s = 15.5 (Incorrect option)

J. –1 + s = 10.5

s = 10.5 + 1

s = 11.5 (Incorrect option)

5 0

3 years ago

Need help with finding the area of this

dusya [7]

In the given figure, there are two right angled triangles.

Area of triangle = 1/2 × b × h

Area of shaded region = area of larger triangle - area of smaller triangle

= 1/2 × 15 × 18 - 1/2 × 8 × 9

= 135 - 36

= 99 ft^2

Thus, area of shaded region is 99 ft^2.

3 0

3 years ago