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3 years ago

Work out the circumference of a circle with diameter 1.8

Mathematics

2 answers:

dalvyx [7]3 years ago

5 0

5.66 (3 significant figures)

ZanzabumX [31]3 years ago

4 0

5.65 when rounded :)

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Find x and the measure of each side.

Anna71 [15]

Answer:

x=27.5

FG=72.5

GH=60

HF=47.5

Step-by-step explanation:

Sum of angles in a triangle=180

Therefore, FG+GH+HF=180

Substituting the values we have,

(3x - 10) + (2x+5) +(x+20) = 180

Collecting like terms

3x+2x+x = 180 +10 - 5 - 20

6x = 165

X= 27.5

FG = (3x - 10) = 3(27.5) - 10

FG= 72.5

GH= (2x+5) = 2(27.5)+5

GH=60

HF= x+20 =27.5+20

HF=47.5

5 0

1 year ago

Locate√3 on number line and jusitify

alekssr [168]

Root3 would be between 1 and 2 on the number line. This is known because 1 squared is 1, and 2 squared is 4.

8 0

3 years ago

What is the following product?

Aneli [31]

Your correct it’s the first one

4 0

3 years ago

HELP ASAP!! <br> solve for e: x/e - r/n = y

nataly862011 [7]

I don’t get what we have to do here sorry I can’t answer it
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3 0

2 years ago

A woman walks due west on the deck of a ship at 3 mi/h. The ship is moving north at a speed of 22 mi/h. Find the speed and direc

Minchanka [31]

Answer: The speed is 22.2 mi/hr and woman is 8° north relative to the surface of the water.

Step-by-step explanation:

Since we have given that

Speed at which woman walks due west = 3 mi/hr

Speed at which ship moving due north = 22 mi/hr

Now it forms "Pythagorus theorem":

So, it becomes,

$H^2=B^2+P^2\\\\H^2=3^2+22^2\\\\H^2=9+484\\\\H^2=493\\\\H=\sqrt{493}\\H=22.20\ mi/hr$

And the direction of the woman relative to the surface of the water is given by

$\theta=\sin^{-1}x(\dfrac{3}{22.2})=7.76\approx 8^\circ$

Hence, the speed is 22.2 mi/hr and woman is 8° north relative to the surface of the water.

5 0

3 years ago