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The square box is enough to fit the pizza with a diameter of 10 inches inside. Since the area of the square box is more than the area of the pizza, the pizza fits easily in the square box.
<h3>What is the area of the circle and the square?</h3>
The area of the circle is
Ac = πr² = πd²/4 sq. units
Where r is the radius and d is the diameter of the circle.
The area of the square is given by
As = s² sq. units
Where s is the length of the side of a square.
<h3>Calculation:</h3>
It is given that a pizza(in a circular shape) with a diameter d = 10 in is to be placed in a square box of the same length as the diameter of the pizza.
So,
The area of pizza is
Ap = Ac = πd²/4 sq. units
= π(10)²/4
= 25π
= 78.54 sq. in
Then, the area of the square box with the length same as the diameter of the pizza is,
As = d²
= 10²
= 100 sq. in
Since the area of the square is more than the area of the pizza (100 sq. inch > 78.54 sq. inch), the pizza easily fits into the square box.
Learn more about the area of a circle here:
brainly.com/question/15673093
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The slope is 1 because it is parallel and y=x+b, so, 2=-3+b and b=5
y=x+5
Length =l
Height = h
Area function = l * h = 924
Perimeter function = 2i + 2h = 122
Divide by 2
I + h = 61.
Plug in I or h for the other variable
I * (61 - I) = 924
61i - i^2 = 924
Factor the function
(-I + 28)(I - 33) = 0
l = 33 as l cannot be negative
61 - 33 = 28
h = 28
Difference between h and l is 33-28=5
True because they have the same size angles