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2 years ago

Solve each proportion.

Mathematics

1 answer:

Maslowich2 years ago

3 0

To solve this question you need to cross multiply

So first do 3(2x+1) = 4(3x-2)
Which gives you 6x+1 = 12x-8

Now you solve it like a normal equation
6x+1 = 12x-8
9 = 6x
3/2 = x

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A square has sides 5.3cm long. Work out the area of the square

mezya [45]

Answer:

Area of square = 28.09 square cm.

Step-by-step explanation:

Given : A square has sides 5.3 cm long.

To find : Work out the area of the square.

Solution : We have given

Side of square = 5 .3 cm .

Area of square = side * side .

Area of square = 5.3 * 5.3 .

Area of square = 28.09 square cm.

Therefore, Area of square = 28.09 square cm.

4 0

3 years ago

Toni rides the Ferris wheel shown for 15 revolutions. A photo of a Ferris wheel has the diameter labeled fifty-six feet. Questio

NARA [144]

Answer:

a. 176 feet b. 2640 feet

Step-by-step explanation:

a. Since the diameter of the Ferris wheel is D = 56 feet, the distance Toni travels in one revolution is the circumference of the Ferris wheel, C = πD.

So C = 22/7 × 56 ft = 22 × 8 ft = 176 feet

b. The distance traveled in 15 revolutions is thus D' = 15 × distance of one revolution = 15 × 176 = 2640 feet

5 0

3 years ago

The sum of 5 consecutive integers is 120. What is the third number in this sequence?

aliina [53]

Ok so

x - the smallest
The other 4 are : x+1, x+2, x+3, x+4
We know that sum is 120
So
x+x+1+x+2+x+3+x+4=120
Combine like terms
5x+10=120
Subtract 10 on both sides
5x=120-10
5x=110
Divide by 5 on both sides
X=22
The third number is x+2 = 22+2=24

3 0

3 years ago

Find all of the points of the form (x −1) which are 4 unit from the point (3,2)

Bond [772]

Answer:

$(3+2\sqrt{2},2+2\sqrt{2}),(3-2\sqrt{2},2-2\sqrt{2})$

Step-by-step explanation:

$Points\ are\ of\ the\ form\ (x,x-1)\\\\Distance\ of\ these\ points\ from\ (3,2)=4\\\\\sqrt{(x-3)^2+(x-3)^2}=4\\\\\sqrt{(x-3)^2+(x-1-2)^2}=4\\\\\sqrt{2(x-3)^2}=4\\\\2(x-3)^2=16\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ square\ both\ the\ sides\\\\(x-3)^2=\frac{16}{2}\\\\(x-3)^2=8\\\\(x-3)=\pm 2\sqrt{2}\ \ \ \ \ \ \ \ \ \ \ square\ root\ both\ the\ sides\\\\x=3\pm 2\sqrt{2}\\\\When\ x=3+2\sqrt{2}\ \ \Rightarrow x-1=3+2\sqrt{2}-1=2+2\sqrt{2}\\\\When\ x=3-2\sqrt{2}\ \ \Rightarrow x-1=3-2\sqrt{2}-1=2-2\sqrt{2}$

4 0

3 years ago

How do I Expand (2x − 1)^6

Veronika [31]

Answer:

well if u do this

(2x-1)(2x-1)(2x-1)(2x-1)(2x-1)(2x-1)

it would be the expanded form for (2x-1)^6

Step-by-step explanation:

i um learned it before so...

6 0

2 years ago