12. Linda walks through a road. If her walking speed increases from 1 m/s to 1.5 m/s, she will complete the walk 200 s earlier.
Find the distance travelled by Linda.
1 answer:
Answer:
<u>600 meters</u>
Step-by-step explanation:
<u>Case 1 : Speed of 1 m/s</u>
- d = v * t
- d = 1 * t
- d = t [Equation 1]
<u>Case 2 : Speed of 1.5 m/s</u>
- d = v * t
- d = 1.5 * (t - 200)
- d = 1.5t - 300 [Equation 2]
As distance in both cases is the same, equate the values of d from both equations.
- t = 1.5t - 300
- 0.5t = 300
- t = 300 * 2
- <u>t = 600 s</u>
Now, put the value of t in <u>Equation 1</u> to find d.
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