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Vladimir [108]
1 year ago
11

12. Linda walks through a road. If her walking speed increases from 1 m/s to 1.5 m/s, she will complete the walk 200 s earlier.

Find the distance travelled by Linda.​
Mathematics
1 answer:
Katen [24]1 year ago
7 0

Answer:

<u>600 meters</u>

Step-by-step explanation:

<u>Case 1 : Speed of 1 m/s</u>

  • d = v * t
  • d = 1 * t
  • d = t       [Equation 1]

<u>Case 2 : Speed of 1.5 m/s</u>

  • d = v * t
  • d = 1.5 * (t - 200)
  • d = 1.5t - 300 [Equation 2]

As distance in both cases is the same, equate the values of d from both equations.

  • t = 1.5t - 300
  • 0.5t = 300
  • t = 300 * 2
  • <u>t = 600 s</u>

Now, put the value of t in <u>Equation 1</u> to find d.

  • d = <u>600 meters</u>
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Answer:

x = 70°

Step-by-step explanation:

Itz given that AB & CD are perpendicular to each other and intersect at E . So , angle(AED) = 90°

But here the value of angle(AED) = 90°

So,

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3 0
3 years ago
A gambler playing blackjack in a casino using four decks noticed that 20% of the cards that had been dealt were jacks, queens, k
Ksenya-84 [330]

Answer:

x = 162 cards need to be dealt with

Step-by-step explanation:

Given:

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For what values of x is this likelihood greater than 70%?

Solution:

- Use the likely-hood estimation relation and set up the inequality as follows:

                                 ( 64 - 0.2*x ) / ( 208 - x ) > 0.7

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                                   64 - 0.2*x > 145.6 - 0.7*x

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nirvana33 [79]

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3 years ago
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kobusy [5.1K]

Answer:

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Step-by-step explanation:

replace

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Mkey [24]

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Answer:

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