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Dahasolnce [82]
3 years ago
5

Stefanie is painting her bedroom. She can paint 12 1/3 square feet in 4/5 of an hour. How many square feet can she paint in one

hour?
Mathematics
1 answer:
Lapatulllka [165]3 years ago
3 0

Answer:

30 5/6 square feet

Step-by-step explanation:

And my bad

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the formula y-y1 =m(x-x1) is the pot slope form of the equation of a line where m is the slope of the line and(x,y) and (x1,y1)
oksano4ka [1.4K]
\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~{{ 4}} &,&{{ -2}}~) 
%  (c,d)
&&(~{{ 5}} &,&{{ 0}}~)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{5-(-2)}{0-4}\implies \cfrac{5+2}{0-4}\implies -\cfrac{7}{4}

\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-2)=-\cfrac{7}{4}(x-4)
\\\\\\
y+2=-\cfrac{7}{4}(x-4)\implies y+2=-\cfrac{7}{4}x+7\implies y=-\cfrac{7}{4}x+9
6 0
3 years ago
Thank you guys so much
jeka57 [31]

Answer:

B. City P is above sea level and City R is below sea level

Step-by-step explanation:

A. City R is negative meaning it is below sea level however City Q is 0 meaning it is at sea level, so this statement is false.

C. Once again, City P is positive meaning it is above sea level but City Q is 0 meaning it is at sea level, so this statement is false.

D. Like before, City P is above sea level and City Q is at sea level not below, so this is, once again, false.

6 0
2 years ago
If the diameter of Pluto is 1475 miles and an orbiting space station is circling 25 miles above the Pluto's surface, find the di
omeli [17]

Answer:

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Step-by-step explanation:

7 0
3 years ago
Can someone please help I will give you 30 points and brainliest if the answer is right also no links please
Zolol [24]

Answer:

B: BC ≅EC

Step-by-step explanation:

You know that the two angles starting in C are congruent (they're opposite by vertex C).

Given that the B angle and the E angle are congruent, in order for the two triangles to be congruent by A(ngle)S(ide)A(ngle) you want the side inbetween to be congruent. That is BC and EC. Option B

5 0
2 years ago
A survey of 25 young professionals fond that they spend an average of $28 when dining out, with a standard deviation of $10. (a)
skad [1K]

Answer:

a) The 95% of confidence intervals for the average spending

(23.872 , 32.128)

b) The calculated value t= 1< 1.711( single tailed test) at 0.05 level of significance with 24 degrees of freedom.

The null hypothesis is accepted

A survey of 25 young professionals statistically that the population mean is less than $30

<u>Step-by-step explanation</u>:

Step:-(i)

Given data a survey of 25 young professionals fond that they spend an average of $28 when dining out, with a standard deviation of $10

The sample size 'n' = 25

The mean of the sample   x⁻  = $28

The standard deviation of the sample (S) = $10.

Level of significance ∝=0.05

The degrees of freedom γ =n-1 =25-1=24

tabulated value t₀.₀₅ = 2.064

<u>Step 2:-</u>

The 95% of confidence intervals for the average spending

((x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )

(28 - 2.064 \frac{10}{\sqrt{25} } ,28 + 2.064\frac{10}{\sqrt{25} } )

( 28 - 4.128 , 28 + 4.128)

(23.872 , 32.128)

a) The 95% of confidence intervals for the average spending

(23.872 , 32.128)

b)

Null hypothesis: H₀:μ<30

Alternative Hypothesis: H₁: μ>30

level of significance ∝ = 0.05

The test statistic

t = \frac{x^{-}-mean }{\frac{S}{\sqrt{n} } }

t = \frac{28-30 }{\frac{10}{\sqrt{25} } }

t = |-1|

The calculated value t= 1< 1.711( single tailed test) at 0.05 level of significance with 24 degrees of freedom.

The null hypothesis is accepted

<u>Conclusion</u>:-

The null hypothesis is accepted

A survey of 25 young professionals statistically that the population mean is less than $30

8 0
2 years ago
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