Let A = 0.0009, it is equivalent to A = 9^-4 = (9^-2)^2
so sqrt A =sqrt (9^-2)^2 = (9^-2)
<span>he real square roots of 0.0009 is 0.09</span>
Answer:
a>-21(1/3)
Step-by-step explanation:
3/4a>-16
first thing is to divide both sides by 3/4 to isolate the variable.
Since it is not negative, the sign stays the same.
-16/0.75=-21.3 repeating or just 1/3
Square x first then add x then subtract by 2
Give me the brainliest if u like the answer
f(x)•g(x) = (5x+7)×(x-9)
now multiply 5x with both terms and 7 with both terms