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Rus_ich [418]
3 years ago
13

okay so on my homework assignment it says find the area of a semicircle but we never went over finding the area of that. Can som

eone help? (the diameter is 24 btw)
Mathematics
2 answers:
laila [671]3 years ago
4 0
Area of semicircle=.5×22/7×144
HENCE U CAN FIND THE ANSWER
eimsori [14]3 years ago
3 0
Okay so s semicircle hmm. Thats semi-of-a-circle. So half would be fine.  
Then do the equation set up for area of a CIRCLE not s spere. 
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Mr. Hodges wants to build a fence around his entire rectangular garden which has sides of 30 feet and 6 yards. How much fencing
horrorfan [7]
Mr Hodges will need 63 feet of fencing
5 0
3 years ago
Your basketball team scored 4 fewer than twice as many points, x, as the other team. a. Write an expression for the number of po
velikii [3]

Answer:

A) p = 2x - 4  for the expression. B) Your team scored 44 points.

Step-by-step explanation:

Let <u>P</u> represent the points your team made.

Since the question says "Your basketball team scored 4 fewer than twice as many points as the other team." this is how I came up with the expression.

p = 2x - 4 ( our points = 2 times more then the other teams points minus 4.

Using this expression and the given information that the other team made 24 points, I solved B.

44 = 2(24) - 4.

3 0
3 years ago
Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = 3x2 − 2x + 1, [0, 2] Yes, it do
expeople1 [14]

Answer:

Yes , function is continuous in [0,2] and is differentiable (0,2) since polynomial function are continuous and differentiable

Step-by-step explanation:

We are given the Function

f(x) =3x^2 -2x +1

The two basic hypothesis of the mean valued theorem are

  • The function should be continuous in [0,2]
  • The function should be differentiable in (1,2)

upon checking the condition stated above on the given function

f(x) is continuous in the interval [0,2] as the functions is quadratic and we  can conclude that from its graph

also the f(x) is differentiable in (0,2)

f'(x) = 6x - 2

Now the function satisfies both the conditions

so applying MVT

6x-2 = f(2) - f(0) / 2-0

6x-2 = 9 - 1 /2

6x-2 = 4

6x=6

x=1

so this is the tangent line for this given function.

   

4 0
3 years ago
Can anyone help me with this
Wittaler [7]

I believe the right anwser is c

4 0
3 years ago
13. What is the measure of MO?<br> a. 90<br> c. 45<br> b. 180<br> d. Cannot be determined
choli [55]
The answer to this problem is 45
5 0
2 years ago
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