All categories

3 years ago

Help please thanks! :)

Mathematics

1 answer:

Taya2010 [7]3 years ago

7 0

Answer:

Option A = 1/15 cubic meters

Step-by-step explanation:

Formule to find volume of rectangular prism:

Volume = width × height × length

V = w×h×l

V = 1/3 × 1/4 × 4/5

V = 1/15 cubic meters

You might be interested in

Please help, due tomorrow, please do all!

zlopas [31]

Answer:

are we supposed to multiply

Step-by-step explanation:

4 0

3 years ago

Evaluate 6²-7²+8²-9²+..+998²-999²

Llana [10]

Answer:

-499,485.

Step-by-step explanation:

We can transform this to an arithmetic series by working it out in pairs:

6^2 - 7^2 = (6-7)(6+7) = -13

8^2 - 9^2 = (8-9)*8+9) = -17

10^2 - 11^2 = -1 * 21 = -21 and so on

The common difference is -4.

The number of terms in this series is (998 - 6) / 2 + 1

= 992/2 + 1 = 497.

Sum of n terms of an A.S:

= n/2 [2a1 + (n - 1)d

Here a1 = -13, n = 497, d = -4:

Sum = (497/2)[-26 - 4(497-1)]

= 497/2 * -2010

= -499,485.

3 0

3 years ago

Find a linear function g, in slope intercept form, given g(-2)=-3 and g(2)=1

Zigmanuir [339]

G(x)= x-1

Hope this helps!

8 0

3 years ago

If log, 7 -3 what is the value of x?<br> A. 21<br> B. 3V7<br> C. 37<br> D. 343

gregori [183]

Answer:

Step-by-step explanation:

logₓ 7 = 3

x³ = 7

Take cube root both sides

$x= \sqrt[3]{7}$

4 0

3 years ago

When studying radioactive material, a nuclear engineer found that over 365 days, 1,000,000 radioactive atoms decayed to 973 co

HACTEHA [7]

Answer:

A. number of decayed atoms = 73.197

Step-by-step explanation:

In order to find the answer we need to use the radioactive decay equation:

$N(t)=N0*e^{kt}$ where:

N0=initial radioactive atoms

t=time

k=radioactive decay constant

In our case, when t=0 we have 1,000,000 atoms, so:

$1,000,000=N0*e^{k*0}$

$1,000,000=N0$

Now we need to find 'k'. Using the provied information that after 365 days we have 973,635 radioactive atoms, we have:

$973,635=1,000,000*e^{k*365}$

$ln(973,635/1,000,000)/365=k$

$-0.0000732=k$

A. atoms decayed in a day:

$N(t)=1,000,000*e^{-0.0000732t}$

$N(1)=1,000,000*e^{-0.0000732*1}$

$N(1)= 999,926.803$

Number of atoms decayed in a day = 1,000,000 - 999,926.803 = 73.197

B. Because 'k' represents the probability of decay, then the probability that on a given day 51 radioactive atoms decayed is k=0.0000732.

4 0

3 years ago