Write an equation in slope-intercept form for the line that is parallel to y=x−6 and that passes through the point (−5,−6).
1 answer:
Answer:
y = x - 1
- slope of 1, and y-intercept of (0, -1)
Step-by-step explanation:
Note: parallel lines have the same slope
Using the slope-intercept formula (<em>y = mx + b</em><em> - where m is the slpe and b is the y-intercept (when x = 0)</em>) to determine the the slope and y-intercept of the equation:
y = x − 6
- slope of 1, and y-intercept of (0, -6)
Find the equation in slope-intercept form for the line that is parallel to y = x − 6 and that passes through the point (−5,−6):
y = x + b <== substitute -5 for x and -6 for y
-6 = -5 + b <== add 5 to both sides
+5 +5
-1 = b
Equation: y = x - 1
Check your answer using the point:
y = x - 1
-6 = -5 - 1
-6 = -6
This statement is correct
Hope this helps!
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You'll be using point slope form to solve this.
As the name suggests, you'll need the slope as well as a point. To find the slope use the slope formula:
Plug in the points.
The slope of this line is 5.
Point slope form is y-y1 = m(x-x1), so plug in the slope and a point into this equation. I'll use (0,8).
y-(8) = 5(x-(0))
1. Write this out without parentheses.
y-8 = 5(x)
2. Multiply 5 and x.
y-8 = 5x
3. Add 8 to both sides.
y = 5x+8
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Answer is:
y = 5x+8