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goldfiish [28.3K]

3 years ago

15

CAN SOMEONE LOOK AT MY QUESTIONS I NEED HELP ASAP I JUST ASKED A QUESTION YESTERDAY ND I NEED HELP . JUST GO LOOK AT MY QUESTION

S FROM YESTERDAY

1 answer:

Lerok [7]3 years ago

7 0

Answer: sure :)))))))

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Step-by-step explanation:

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Analyzed and Sketched.

Step-by-step explanation:

We are given $y=\frac{\ln\left(5x)}{x^2}$

To sketch the graph we need to find 2 components.

1) First derivative of y with respect to x to determine the interval where function increases and decreases.

2) Second derivative of y with respect to x to determine the interval where function is concave up and concave down.

$y'=\frac{1-2\ln\left(5x)}{x^3}=0$

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$y''=\frac{6\ln\left(5x)-5}{x^4}=0$

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The graph is given in the attachment.

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3 years ago

H(x) = 3x - 1; Find h(3)

vfiekz [6]

Answer:

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Step-by-step explanation:

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