The answer is A It protects the seed until it matures.
hope this helps
ok so I've done this problem before trust me:
A. bundles of microtubules that separate to opposite poles of a cell - CENTRIOLES
B. prepares protein-packed vesicles for release outside of the cell - VESICLES
C. small storage sacs containing water, food, and waste - VACUOLES
D. rough and smooth organelle that produces protein, steroids, and lipids - ENDOPLASMIC RETICULUM
E. tiny sacs at the end of the ER which contain protein - GOLGI COMPLEX
F. chains of protein fibers that provide support and shape - CYTOSKELETON
G. powerful enzymes used to process cellular activity - LYSOSOMES & PEROXISOMES
H. whip-like structures on cells that are used for movement - FLAGELLA
I. produces and assembles proteins - RIBOSOMES
The probability of transmitting both traits to his son is Zero. This is because the son has one X chromosome and one Y chromosome (XX), therefore since the traits are linked to the X chromosomes, it means the son will only be a carrier but will not show the trait phenotypically.
The production of egg and sperm cells follows a certain sequence of events.
The correct order of those events are:
MEIOSIS, CELL DIFFERENTIATION, MATURE GAMETES.
Meiosis is defined as the process wherein a single cell is divided twice to produce four cells that contains half the original amount of genetic information.
Cell differentiation is defined as the process wherein the less specialized cell becomes a more specialized cell. The haploid cells are the end result of meiosis. They must undergo cell differentiation before they can become mature gametes.
This is due to the fact that women usually become infected at younger age than men. Many young women have a sexual relationship with older men who are more likely a hiv-positive, with the result that far more young women that young men in Africa were infected. Also the women are at higher risk of infection. The reason is both physical and socio-cultural.
