Answer:92.53
Step-by-step explanation:95×2.6℅=2.47
95-2.47=92.53
p = 2(l+w)
divide by 2
p/2 = l+w
subtract l from both sides
p/2 - l = 2
Choice c
Answer:
0.3667 or 36.67%
Step-by-step explanation:
The probability of getting at least 1 defective hard disk among the 5 (P(X>0)) is equal to 100% minus the probability of getting none defectives (1-P(X=0)).
If 23 out of 25 hard disks are non-defective, the probability is:

The probability that there is at least 1 defective hard disk is 0.3667 or 36.67%.
For the first one it would be 10/3 ( 10 over 3 ) and for the second one, it would be 7/13 ( 7 over 13 ) PLUS 4i/13 ( 4i over 13)