If b is in the first position then c can be in any 1 of the remaining 6 positions.
If we start with ab then the letter c can be in any one of 5 positions and if we have aab there are 4 possible positions for c and so on.
So the total number of possible sequences where b comes first = 6+5+4+3+2+1 = 21.
The same argument applies when c comes before b so that gives us 21 ways also.
So the answer is 2 *21 = 42 different sequences.
A more direct way of doing this is to use factorials:-
answer = 7! / 5! = 7 * 6 = 42.
( We divide by 5! because of the 5 a's.)
Answer:
y = x - 2
Step-by-step explanation:
You can subtract 4 from the x and y to get where the y-intercept would be.
5n-4 = 6 gives the equation for 5 times #Nathan rode less 4 miles which solves to n = 2
Nathan rode 2 miles. (5*2)-4 = 6 10-4=6 so 2 miles is right
The linear relationship which exists between the change in weight and number of days of hibernation in a hedgedog can be modeled using the equation y = - 0.03 + 0
- Change in weight per day of hibernation = - 0.03
- Change in weight for 115 days = - 3.45 ounces
A linear model can be created using the data in the table given using a regression calculator or excel ;
The linear model obtained in the form y = m + bx is :
- y = - 0.03x + 0
- y = change in weight
- x = number of days of hibernation
- Intercept = 0
- Slope = -0.03
- The slope value of the function gives the change in weight value per number of days of hibernation ; which is -0.03.
- Using the regression equation, substitute, the vlaue of x = 115
- -0.03(115) + 0 = - 3.45
Therefore, the change in weight after 115 days of hibernation is - 3.45 ounces.
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5/6 of an hour is 50 min. So 50 times 3 equals 150 min for reading. 3/4 of an hour is 45 min. 45 times 2 equals 90 min for science. And 1/2 of an hour is 30 min. So 30 times 4 equals 120 mins for math. Add 150,90, and 120 min all together and you get 360 mins total. Divide 360 by 60, and you get 6 hours total that Michaela spent on reading, math, and science. Not 2 1/2.