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nikitadnepr [17]
3 years ago
13

Evaluate k(x) = -k - 7 when k(-4)

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
8 0

Answer:

I'm not sure but i think that it's

x= -7

Hope this helps

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A cylinder has a base radius of 3 inches and a height of 3 inches. What is its volume in cubic inches, to the nearest tenths pla
Alika [10]
84.8 is the answer hope this helps
6 0
3 years ago
6.8x+9.3 = -9.4+3,4(2-5x)<br> 6.8x+9.3 = -9.4+6.8 -17<br> 6.8x+9.3 = -2.6-17x
Advocard [28]

Answer:

x = -0.5

Step-by-step explanation:

From your last step:

6.8x + 9.3 = -2.6 - 17x

We have two terms with x in them on different sides of the equation, so we want to bring the 'x terms' over to the same side.

Add 17x to both sides of the equation.

6.8x + 17x + 9.3 = -2.6

Collect like terms

23.8x + 9.3 = -2.6

Subtract 9.3 from both sides

23.8x = -2.6 - 9.3

23.8x = -11.9

Divide both sides by 23.8

x = -0.5

7 0
4 years ago
The measure of b is..
sladkih [1.3K]

Answer:

b =21

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a  and b are the legs and c is the hypotenuse

20^2 + b^2 = 29^1

400 + b^2 =841

Subtract 400 from each side

b^2 = 441

Take the square root of each side

sqrt(b^2) = sqrt(441)

b =21

7 0
3 years ago
Read 2 more answers
On December 13, 2007, one British pound was worth 2.04 U.S. dollars.
Alika [10]

Answer:

a) 5 pounds

b) 365 dollars

3 0
2 years ago
A dog and a cat are 200 meters apart when they see each other. The dog can run at a speed of 30 meter per second, while the cat
LenKa [72]

Answer:

They'll meet after 200 meters , if they simultaneously start running towards each other.

Step-by-step explanation:

Let x =distance travelled by dog and 200-x be the distance travelled by cat. Inorder to meet, the sum of their travelled distances shall be equal to 200 meters as they are far apart by 200 meters.

Dog: Distance =Speed x time: x=30t

Cat: Distance = 200-x

=24t

The sum of their distance travelled shall be 200 meters: 30t+ 24t= 200;54t=200;t=200/54=3.7secs

So they will meet after 3.7 seconds

To check:

Distance travelled by dog :x=30(3.7)

=111.11 meters

Distance travelled by cat: 24t=24(3.7)

=88.89 meters

Therefore since they are travelling towards each other and their distance apart is 200 meters, after 3.7 seconds they will meet because dog travelled 111.11 meters and cat travelled 88.89 meters and they covered already 200 meters as the sum of 111.11+ 88.89

=200 meters

6 0
2 years ago
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