It has no real solutions. To be precise, no real zeros (or roots).
The zeros (here called "solutions", I guess) are the points where the function intersects the x-axis: at those points the value of the function is zero. So they are solutions to the equation f(x)=0.
This function does not intersect the x-axis. Hence, no solutions.
Try to do the answer of -4
Answer:
20
Step-by-step explanation:
y+4=−12(x−2)
Step 1: Add -4 to both sides.
y+4+−4=−12x+24+−4
y=−12x+20
Answer:
I’m not sure what this question is asking, but I’ll write an equation of this circle you are describing. Here, the x coordinate of the center is h, the y coordinate is k, and radius is r in the equation : (x-h)^2+(y-k)^2=r^2, meaning the equation in this situation is the following: (x-2)^2+(y-8)^2=9
Step-by-step explanation:
Slope = "rise over run" the difference in y values divided by the difference in x values
= 6/-3 = -2 = m. It's negative because as x increases, y decreases
plug that into the point slope formula, with either point. generally use the most simple point
y-h= m(x-k) where m= -2 and (k,h) = (2,-2)
y+2 = -2(x-2)
simply if you want
Y = -2x +4 -2 = -2x +2
or
2x +y = 2
