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Semenov [28]
3 years ago
7

before his shopping spree, Elmer owned 52 scooters. Then he bought 82 more scooters. what is the ratio of scooters purchased to

the resulting total number of scooters.
Mathematics
1 answer:
laiz [17]3 years ago
6 0

Answer:

Step-by-step explanation:

82 / (52+82)

82 / 134

41 / 67  

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Solve for x<br><br> 2/7x = 6<br><br> (SHOW YOUR WORK)
castortr0y [4]

Answer:

The answer to your question is  x = 21

Step-by-step explanation:

Equation

                                       \frac{2}{7} x = 6

- Multiply both sides by 7

                                        \frac{(2)(7)x}{7} = 6(7)

- Simplify

                                        2x = 42

- Divide both sides by 2

                                         \frac{2x}{2} = \frac{42}{2}

- Simplify

                                         x = 21

5 0
3 years ago
Read 2 more answers
Suppose 50 members of the sixth-grade class raise a total of +740
sineoko [7]

Answer:

im pertty sure $740

Step-by-step explanation:

3 0
3 years ago
How much fencing does Farmer Gump need?
Agata [3.3K]

For the first field, he will need 40 m for the fence, this will cost £640 and he can have 10 sheep. For the second field, he will need 60 m for the fence, this will cost  £960 and he can have 12 sheep.

<h3>What does this problem require?</h3>

This problem requires you to calculate the perimeter and area of each field and based on this information you can find the total of the fence the farmer requires, the cost, and the number of sheep.

<h3>How to calculate the perimeter?</h3>

You can calculate the perimeter by adding all the sides.

  • Field 1: 10m + 10m + 10m + 10m = 40 m
  • Field 2: 25m + 5m + 25m + 5m = 60 m

<h3>How to calculate the area?</h3>

To calculate the area, multiply the height by the width.

  • Field 1: 10 x 10 = 100m2
  • Field 2: 25 x 5 = 125m2

<h3>How much fencing does the farmer need?</h3>

The fencing needed is equal to the perimeter.

  • Field 1: 40 m of fencing
  • Field 2: 60 m of fencing

<h3>How much will it cost?</h3>

Multiply the number of meters needed by the price per meter ( £16 per meter).

  • Field 1: 40m x  £16 per meter = £640
  • Field 2: 60 m x £16 per meter = £960

<h3>How many sheep can there be in each field?</h3>

To calculate this divide the area into the space required by each sheep (10m2).

  • Field 1: 100m2 / 10m2 = 10 sheep
  • Field 2: 125m2 /10m2 = 12 sheep

Note: This question is incomplete; here is the missing information:

Farmer Gump has two problems. His first problem is to work out how much fencing he needs to buy for his fields so his sheep don’t escape. His second problem is to work out how many sheep each field can hold—each sheep needs a minimum of 10m² of grass!

Sheep cost £65 each.

The fence is £16 per meter.

Learn more about perimeter in: brainly.com/question/6465134

4 0
3 years ago
What are the opposites of 5, −2.6, 2.25, and 7 1 4 ? Enter the answers in respective order, each separated by comma.
arsen [322]
-5, 2.6, -2.25,and -714
7 0
3 years ago
What is a perfect square? Why is <img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%208x%20%2B16" id="TexFormula1" title="x^{2}
ivanzaharov [21]

Answer:

It is a perfect square. Explanation below.

Explanation:

Perfect squares are of the form

(

a

+

b

)

2

=

a

2

+

2

a

b

+

b

2

. In polynomials of x, the a-term is always x.(

(

x

+

c

)

2

=

x

2

+

2

c

x

+

c

2

)

x

2

+

8

x

+

16

is the given trinomial. Notice that the first term and the constant are both perfect squares:

x

2

is the square of x and 16 is the square of 4.

So we find that the first and last terms correspond to our expansion. Now we must check if the middle term,

8

x

is of the form

2

c

x

.

The middle term is twice the constant times x, so it is

2

×

4

×

x

=

8

x

.

Okay, we found out that the trinomial is of the form

(

x

+

c

)

2

, where

x

=

x

and

c

=

4

.

Let us rewrite it as

x

2

+

8

x

+

16

=

(

x

+

4

)

2

. Now we can say it is a perfect square, as it is the square of

(

x

+

4

)

.

3 0
3 years ago
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