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2 years ago

I need help with this plssssssssssssss

Mathematics

1 answer:

myrzilka [38]2 years ago

4 0

Answer:

its D

Step-by-step explanation:

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Simplify 4(6n+9)-10n please help

loris [4]

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3 years ago

What is the answer for 6?

marusya05 [52]

IS the answer ii and iv

and the other is y<5.3

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3 years ago

5tanx-2cotx+1=0...... .

Verdich [7]

Step-by-step explanation:

5(tanx)^2 -2 +tanx=0

let tanx=y

5y^2 + y-2=0

y=0.5403 or y= -0.7403

tanx=0.5403

x=arctan(0.5403)

x=28.38°

tanx=-0.7403

x=arctan(-0.7403)

x=143.49°

7 0

3 years ago

MULTIPLE CHOICE PLS ANSWER

zubka84 [21]

Answer:

Option.B

Step-by-step explanation:

Its because if you add these two angles you get a supplementary angle or 180°

Using this we can form an equation to find the value of x.

(Hope this answer helps :))

(And is this question from Khan Academy?)

5 0

3 years ago

Select the correct answer from each drop-down menu.

finlep [7]

Answer:

Coordinates of point B are (10,-4)

Coordinates of point D are (3.6,-0.4)

Step-by-step explanation:

1) Point C(3.6, -0.4) divides in the ratio 3 : 2. If the coordinates of A are (-6, 5), the coordinates of point B are ____

Let the coordinates of B be $(x_2,y_2)$

Coordinates of A = $(x_1,y_1)=(-6,5)$

Coordinates of C=(x,y)=(3.6,-0.4)

We will use section formula over here

$x=\frac{mx_2+nx_1}{m+n} , y = \frac{my_2+ny_1}{m+n}$

m:n=3:2

$3.6=\frac{3x_2+2(-6)}{3+2} , -0.4=\frac{3y_2+2(5)}{3+2}3.6 \times 5 = 3x_2-12, -0.4 \times 5 = 3y_2+10\\18+12=3x_2 , -2=3y_2+10\\30=3x_2 , -12=3y_2\\10=x_2, -4=y_2\\$

Coordinates of B = (10,-4)

2)If point D divides in the ratio 4 : 5, the coordinates of point D are ____

(fraction)

Let the coordinates of D be $(x,y)$

Coordinates of A = $(x_1,y_1)=(-6,5)$

Coordinates of B= $(x_2,y_2)=(10,-4)$

We will use section formula over here

$x=\frac{mx_2+nx_1}{m+n} , y = \frac{my_2+ny_1}{m+n}$

m:n=3:2

$x=\frac{3(10)+2(-6)}{3+2} , y=\frac{3(-4)+2(5)}{3+2}\\x=3.6,y=-0.4$

Coordinates of point B are (10,-4)

Coordinates of point D are (3.6,-0.4)

4 0

3 years ago