We have been given graph of a downward opening parabola with vertex at point 
. We are asked to write equation of the parabola in standard form.
We know that equation of parabola in standard form is 
.
We will write our equation in vertex form and then convert it into standard form.
Vertex for of parabola is 
, where point (h,k) represents vertex of parabola and a represents leading coefficient.
Since our parabola is downward opening so leading coefficient will be negative.
Upon substituting coordinates of vertex and point (0,0) in vertex form, we will get:
Divide both sides by 
So our equation in vertex form would be 
.
Let us convert it in standard from.
Therefore, the equation of function is standard form would be .
Answer:
what are you saying
Step-by-step explanation:
Answer:
(7x+2)(3x-1); (5x+4)^2 or (5x+4)(5x+4);
Step-by-step explanation:
formula to find area is L* W = A ; meaning length multiplied by width equals to the area.
21.
using the formula to find area...
l*w=a
(7x+2)(3x-1) would be your answer
btw, don't put the "=a" at the end, since it's an expression :))
22.
since the problem states that it's a square, you can just say either...
(5x+4)^2 or (5x+4)(5x+4) not sure which one your teacher accepts
...........................
52=2w+2l
52=2(l-8)+2l
52=2l-16+2l
52=4l-16
36=4l
l=9
