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3 years ago

Help I need this done soon!!! Thank you!!

Mathematics

1 answer:

jenyasd209 [6]3 years ago

4 0

D is the midpoint of segment AC, Given
Segment AD is congruent to segment CD, Definition of Midpoint
Angle BDC is congruent to angle BDA, Given
Segment BD is congrent to angle BD, Reflexive property of congruence
Triangle ABD is congruent to triangle CBD, SAS

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One side of a rectangle is 3 cm longer than the other. If the total area of the rectangle is 154 cm, what is the perimeter of th

finlep [7]

Answer:

Perimeter of rectangle = L÷B

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3 years ago

I WILL AWARD BRAINLIEST!! Find the value of x in each case.

kondor19780726 [428]

Angle D is equal to Angle B because AB and DE are parallel to each other.

AD is a straight line so the (2) 2x angles and 72 degrees need to equal 180.

Setting up the equation you have:

2x + 2x + 72 = 180

Simplify:

4x + 72 = 180

Subtract 72 from each side:

4x = 108

Divide both sides by 4:

x = 108 / 4

x = 27

5 0

3 years ago

Please please help me

Nataly_w [17]

Answer:

The average rate of change is 4.

Step-by-step explanation:

It is 4 because when you do the formula to find the rate of change it comes out to be 4.

8 0

3 years ago

Your bill from Acme Supply Company is marked "3/15, net 30." The amount of the bill is $178.95. If you pay the bill within 15 da

Ray Of Light [21]

3/15 means if you pay the bill within 15 you will get a discount by 3%
Now solve your question
178.95−(178.95×0.03)
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5 0

3 years ago

Read 2 more answers

A box has a volume of 308 cm cubed. Its height is 4 cm greater than its length. Its length is 3 cm greater than its width. What

kifflom [539]

Answer:

4 cm.

Step-by-step explanation:

Given:

A box has a volume of 308 cm cubed.

Its height is 4 cm greater than its length.

Its length is 3 cm greater than its width.

Question asked:

What is the width of the box?

Solution:

Let width = $x\ cm$

Length = $x+3\ cm$

Height = $x+3+4=x+7\ cm$

As we know:

$Volume\ of\ box=length\times width\times height$

$308=(x+3)\times x\times(x+7)\\ \\ 308=(x^{2} +3x)(x+7)\\ \\ 308=x^{2} (x+7)+ 3x(x+7)\\ \\ 308=x^{3} +7x^{2} +3x^{2} +21x\\ \\ 308=x^{3} +10x^{2} +21x\\ \\ Subtract\ 308\ from\ both\ sides\\ \\ x^{3} +10x^{2} +21x-308=0\\ \\ factor\ left\ side\ of\ equation\\ \\ (x-4)(x^{2} +14x+77)=0\\ \\ Set\ factors\ equal\ to\ 0.\\ \\ x-4=0 \ or\ x^{2} +14x+77=0\\ \\ \\$

As width can never be in negative, $x= 4\ cm$

By substituting the value:-

Width = $x\ cm$ = 4 cm

Thus, width of the box is 4 cm.

4 0

3 years ago