Answer:
E = 30.37 J
Step-by-step explanation:
Given that,
The spring constant of the spring, k = 300 N/m
The spring is stretched by 0.45 m, x = 0.45 m
We need to find the elastic energy stored in the spring. The formula for the elastic energy is given by :
So, the required elastic energy is equal to 30.37 J.
Answer:
h = 2
Step-by-step explanation:
7h = -(2h-18)
7h = -2h + 18
9h = 18
h = 18/9
h = 2
Answer:
.07 * 15.25 = 1.0675
Step-by-step explanation:
3.2d - 4d = 2.3d + 3...simplify by combining like terms
-0.8d = 2.3d + 3....subtract 2.3d from both sides
-0.8d - 2.3d = 3 ...simplify again
-3.1d = 3...divide both sides by -3.1
d = 3/ -3.1
d = - 0.97
or
3.2d - 4d = 2.3d + 3....multiply the equation by 10, gets rid of the decimals
32d - 40d = 23d + 30....subtract 23d from both sides
32d - 40d - 23d = 30....simplify
-31d = 30...divide by -31
d = -30/31
d = - 0.97
3m + 2n= p solve for n
subtract 3m on both sides
2n = p - 3m
divide both sides by 2
n = p/2 - 3m/2
-----------------------
xy - 5 = k solve for x
add 5 on both sides
xy = k + 5
divide both sides by y
x = k/y - 5/y
