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1 answer:
The answers to this questions would be:
1. A-> (1.5, 1.5) 5. A and B-> 7 units
2. B-> (-2, -1.5) 6. C and D-> 3 units
3. C-> (-3.5, 2) 7. B and D-> 1 unit
4. D-> (0.5, 0) 8. A and D-> 8 units
-------------------------------- WORD PROBLEMS------------------------------------------
9. 8 feet
10a. (-4, -1) 10b. (4, 1)
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The probability that the first two electric toothbrushes sold are defective is 0.016.
The probability of an event, say E occurring is:
Here,
n (E) = favorable outcomes
N = total number of outcomes
Let X = the number of defective electric toothbrushes sold.
The number of electric toothbrushes that were delivered to a store is n = 20.
The number of defective electric toothbrushes is x = 3.
The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:
The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:
Compute the probability that the first two electric toothbrushes sold are defective as follows:
P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes
Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.
Learn more about probability here brainly.com/question/27474070
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