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PolarNik [594]
3 years ago
12

Write an equation for the proportional relationship. Can you compare these two tables?

Mathematics
1 answer:
Viktor [21]3 years ago
8 0

Answer:

Y=1.88x

Step-by-step explanation:

x1=2 x2=3, y1=3.76 y2=5.64

(2, 3.76) (3, 5.64)

m(slope) =5.64-3.76/3-2

m=1.88

y-3.76=1.88(x-2)

y-3.76=1.88x-3.76

Y=1.88x

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A team of 10 players is to be selected from a class of 6 girls and 7 boys. Match each scenario to its probability. You have to d
tankabanditka [31]
The selection of r objects out of n is done in

C(n, r)= \frac{n!}{r!(n-r)!} many ways.

The total number of selections 10 that we can make from 6+7=13 students is 

C(13,10)= \frac{13!}{3!(10)!}= \frac{13*12*11*10!}{3*2*1*10!}= \frac{13*12*11}{3*2}=  286
thus, the sample space of the experiment is 286

A. 
<span>"The probability that a randomly chosen team includes all 6 girls in the class."

total number of group of 10 which include all girls is C(7, 4), because the girls are fixed, and the remaining 4 is to be completed from the 7 boys, which can be done in C(7, 4) many ways.


</span>C(7, 4)= \frac{7!}{4!3!}= \frac{7*6*5*4!}{4!*3*2*1}= \frac{7*6*5}{3*2}=35
<span>
P(all 6 girls chosen)=35/286=0.12

B.
"</span>The probability that a randomly chosen team has 3 girls and 7 boys.<span>"

with the same logic as in A, the number of groups were all 7 boys are in, is 

</span>C(6, 3)= \frac{6!}{3!3!}= \frac{6*5*4*3!}{3!3!}= \frac{6*5*4}{3*2*1}=20
<span>
so the probability is 20/286=0.07

C.
"</span>The probability that a randomly chosen team has either 4 or 6 boys.<span>"

case 1: the team has 4 boys and 6 girls

this was already calculated in part A, it is </span>0.12.
<span>
case 2, the team has 6 boys and 4 girls.

there C(7, 6)*C(6, 4) ,many ways of doing this, because any selection of the boys which can be done in C(7, 6) ways, can be combined with any selection of the girls. 

</span>C(7, 6)*C(6, 4)= \frac{7!}{6!1}* \frac{6!}{4!2!} =7*15= 105
<span>
the probability is 105/286=0.367

since  case 1 and case 2 are disjoint, that is either one or the other happen, then we add the probabilities:

0.12+0.367=0.487 (approximately = 0.49)

D.
"</span><span>The probability that a randomly chosen team has 5 girls and 5 boys.</span><span>"

selecting 5 boys and 5 girls can be done in 

</span>C(7, 5)*C(6,5)= \frac{7!}{5!2} * \frac{6!}{5!1}=21*6=126

many ways,

so the probability is 126/286=0.44
6 0
3 years ago
Read 2 more answers
Rose bought 7/20 of candy and 0.4 killogram of fruit which did she buy more of explain your answer
Juliette [100K]

Simplify 7/20 to decimals by dividing.

7 divided by 20= 0.35

Rose bought 0.35 kilograms of candy and 0.4 kilograms of fruit.

So, she bought more fruit, since 7/20 is less than 0.4.

I hope this helps :)

6 0
3 years ago
How do you find the lateral area of a pentagonal prism?
Sloan [31]
AL=5ah!!!!!!!!!! Hope it helps
3 0
2 years ago
A dog weighs two pounds less than three times the weight of a cat. The dog also weights twenty-two more pounds than the cat. Wri
Solnce55 [7]

Answer:

the cat weighs 21 pounds.

the dog weighs 43 pounds

Step-by-step explanation:

dog = 3x-20 = x + 22

cat = x

3x-20 = x+22

3x = x+42 (add 20 to both sides)

2x = 42 (subtract x from both sides)

x = 21

4 0
3 years ago
Assume GDP is $19 billion. If consumer spending is $8 billion, financial investment is $2 billion, investment spending is $5 bil
Mila [183]
Answer W at -4 billion is the answer.
5 0
3 years ago
Read 2 more answers
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