This one is worded oddly, but I think it's going to be:
(2x)/19
First you have to make them to a common denominator.
5/6 7/12 7/10
50/60 35/60 42/60
from these the greatest value is 35/60 because 35 parts of 60 is bigger than the rest.
so the answer is 7/12
Answer:
(r o g)(2) = 4
(q o r)(2) = 14
Step-by-step explanation:
Given


Solving (a): (r o q)(2)
In function:
(r o g)(x) = r(g(x))
So, first we calculate g(2)




Next, we calculate r(g(2))
Substitute 9 for g(2)in r(g(2))
r(q(2)) = r(9)
This gives:


{

Hence:
(r o g)(2) = 4
Solving (b): (q o r)(2)
So, first we calculate r(2)




Next, we calculate g(r(2))
Substitute 3 for r(2)in g(r(2))
g(r(2)) = g(3)




Hence:
(q o r)(2) = 14