Longer fat chains are generally digested in the lipeds
Answer:
Lamellae
Explanation:
Chloroplasts are plant (also found in algae) organelles in which photosynthesis occurs. These structures contain pigments (such as chlorophyll) that have the ability to absorb light energy and convert it to sugars necessary for the growth and development of the plant.
Structure of the chloroplast: They are disc-shaped with outer and inner membranes and intermembrane space between them. Inside the chloroplast there is a fluid-filled space called stroma. Stroma contains membrane discs – thylakoids that are arranged in interconnected stacks called grana. In the thylakoid membrane is chlorophyll and inside the thylakoid disc is the space called the thylakoid space.
Answer: secondary b
Explanation: its when there is soil to start with
Question is incomplete. Complete question is as follows:
You have decided to determine how many microbes are living on the lettuce in the salad bar at your favorite restaurant. You place 1 gram of lettuce and 99 mls of water in a blender and blend the mixture. This is sample A. You then transfer 1 ml of this dilution into to another that contains 9 mls of water. This becomes sample B. You next transfer 1 ml of sample B into a separate container that contains 9 mls of water. This is sample C. Next you transfer 1 ml each from samples B & C onto separate nutrient rich agar plates, swirl, let harden and incubate at 37C. When you examine the plates after 48 hours you find 110 colonies growing on plate C. How many microbes were living on that 1 gram of lettuce?
Answer:
1.1x10^6 microbes
Explanation:
When 1gm of lettuce is mixed with 99 ml of water, the microbe concentration is diluted 100 times (Sample A). 1 ml of sample A is mixed with 9ml of water to make sample B which further dilutes microbe concentration 10 times making the total dilution 1000 times. This process is repeated with sample B to make sample C increasing the dilution to 10000 times.
110 colonies are counted from this sample C. Each colony signifies a single microbe during plate counting method. So, 110 microbes were present on the plate. Original number of microbes = microbes counted * times of dilution =
110 * 10000 = 1100000 = 1.1x10^6 microbes
