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oee [108]
3 years ago
11

Calculate the approximate percent increase in luciferase activity between cells containing plasmid pCD3γ-59 and cells containing

plasmid pCD3γ-149. Round to the nearest whole number.
Biology
1 answer:
hodyreva [135]3 years ago
5 0

<u>Incomplete question. Here's the full question</u>;

Identify the plasmid that must contain the CD3γ core promoter sequence but the fewest or no negative regulatory sequences. Based on the data in Figure 2, describe the most likely cause of the variation in luciferase activity among the cells that contain plasmids pCD3γ-419 , pCD3γ-309 , pCD3γ-239 , and pCD3γ-199 . Calculate the approximate percent increase in luciferase activity between cells containing plasmid pCD3γ-59 and cells containing plasmid pCD3γ-149 . Round to the nearest whole number.

<u>Explanation</u>:

Before answering you'll need the image in figure 2 which provides additional details.

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You cross two fruit trees. one tree produces lemons with spiky leaves and bumpy fruit. the other produces lemons with smooth lea
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the alleles are as follows;

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l - lemons with smooth fruit (recessive)

S - smooth leaf (dominant)

s - spiky leaf (recessive)

parents

one tree - lemons with smooth leaves and smooth fruits

<span>one tree - lemons with spiky leaves and bumpy fruits </span>

if parents show recessive phenotype , this means that the genotype should be recessive homozygous - ll / ss

if parents show dominant phenotype genotype is dominant homozygous or heterozygous

<span>parents    -                 S_ ll           x          ssL_</span>

<span>f1generation-</span>

<span> bumpy fruits with smooth leaves - SsLl </span>

<span>bumpy fruits with spiky leaves - </span>ssLl

<span>since offspring are bumpy fruits it should either be Ll /LL, but one parent is ll therefore for the offspring to be Ll/ll the other parent should have homozygous LL. Then the offspring will be heterozygous for fruits</span>

<span>offspring have both spiky leaves - ss and smooth leaves Ss. for offspring to have heterozygous and homozygous both, since one parent is already homozygous, the other parent should have heterozygous alleles- Ss</span>

<span>the parents genotypes are Ssll and ssLL  </span>

<span>             </span>
3 0
3 years ago
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