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viktelen [127]
3 years ago
7

Divide using synthetic division (x^3+5x^2-x-5) divide (x+5)

Mathematics
1 answer:
Kamila [148]3 years ago
8 0

Answer:

Quotient = x^ -1 and the remainder: 0

Step-by-step explanation:

Constant to the left with the opposite sign and coefficients to the right:

-5 | 1 5 -1 -5

Make an horizontal line

Bring down the first coefficient (1) under the line.

Multiply the constant -5 times 1=-5 and add -5 to 5 = 0

Keep doing the same with the coefficients.

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Lines l and m intersect so that the measure of ∠1 is 50°. What is the measure of ∠2?
sergeinik [125]

Answer:

Step-by-step explanation:

Without an illustration, I can’t know the position of ∠2 to ∠1.

If the angles are adjacent then ∠2 = 180° - ∠1 = 130°.

Otherwise, ∠2 = ∠1 = 50°

4 0
3 years ago
(8 -2i)^2 <br>a:60 <br>b:68-32i <br>c:60-32i <br>d:64-32i+4i^2
AURORKA [14]

Answer:

60-32i

Step-by-step explanation:

(8-2i)^2=8^2-2.8.2i+(2i)^2

=64-32i+4i^2

=64-32i-4

=60-32i

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3 years ago
Find the flux of the following vector fields across the given surface with the specified orientation. You may use either an expl
BlackZzzverrR [31]

The tetrahedron passes through the intercepts (5, 0, 0), (0, 2, 0), and (0, 0, 10). Parameterize the surface (call it \Sigma) by

\vec r(u,v)=(1-v)\langle5,0,0\rangle+v\left((1-u)\langle0,2,0\rangle+u\langle0,0,10\rangle\right)

\vec r(u,v)=\langle5(1-v),2(1-u)v,10uv\rangle

with 0\le u\le1 and 0\le v\le1. Take the normal vector to \Sigma to be

\vec r_v\times\vec r_u=\langle20v,50v,10v\rangle

Then the flux of \vec F(x,y,z)=\langle x,y,z\rangle across \Sigma is

\displaystyle\iint_\Sigma\vec F\cdot\mathrm d\vec S=\int_0^1\int_0^1\langle5(1-v),2(1-u)v,10uv\rangle\cdot\langle20v,50v,10v\rangle\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1100v\,\mathrm du\,\mathrm dv=\boxed{50}

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4 years ago
Write the place value of the underlined digit. Round each number to the place of the underlined digit.
nikitadnepr [17]
The 4 is in the Thousands place
3 0
4 years ago
Read 2 more answers
NEED HELP ON THIS PLEASEEEEEEEEEEE
solong [7]

Answer: i am a 7th grade child and i dont know an idea of how to solve this..... just kidding but its b :) hopefully this will help u

Step-by-step explanation:

5 0
3 years ago
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