Geometry question help
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uh, solve for x? Its simple, but first, since it is a prep for a test, you should study how to solve for x, which is easy. So To solve for x, bring the variable to one side, and bring all the remaining values to the other side by applying arithmetic operations on both sides of the equation. Simplify the values to find the result.
Let’s start with a simple equation as, x + 2 = 7
How do you get x by itself?
Subtract 2 from both sides
⇒ x + 2 - 2 = 7 - 2
⇒ x = 5
Now, check the answer, x = 5 by substituting it back into the equation. We get 5 + 2= 7.
L.H.S = R.H.S
And then for a triangle:
Solve for x" the unknown side or angle in atriangle we can use properties of triangle or thePythagorean theorem.
Let us understand solve for x in a triangle with the help of an example.
△ ABC is right-angled at B with two of its legs measuring 7 units and 24 units. Find the hypotenuse x.
then in △ABC by using the Pythagorean theorem,
we get AC2 = AB2 + BC2
⇒ x2 = 72 + 242
⇒ x2 = 49 + 576
⇒ x2 = 625
⇒ x = √625
⇒ x = 25 units
get it? Good
