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3 years ago

7

Lines l and m intersect so that the measure of ∠1 is 50°. What is the measure of ∠2?

1 answer:

sergeinik [125]3 years ago

4 0

Answer:

Step-by-step explanation:

Without an illustration, I can’t know the position of ∠2 to ∠1.

If the angles are adjacent then ∠2 = 180° - ∠1 = 130°.

Otherwise, ∠2 = ∠1 = 50°

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From 145 pounds to 132 pound percent decrease

Airida [17]

145-132= 13

13/145 = 0.089655 rounded to 9

9%

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3 years ago

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Please solve the problem

jek_recluse [69]

Treat the matrices on the right side of each equation like you would a constant.

Let 2<em>X</em> + <em>Y</em> = <em>A</em> and 3<em>X</em> - 4<em>Y</em> = <em>B</em>.

Then you can eliminate <em>Y</em> by taking the sum

4<em>A</em> + <em>B</em> = 4 (2<em>X</em> + <em>Y</em>) + (3<em>X</em> - 4<em>Y</em>) = 11<em>X</em>

==> <em>X</em> = (4<em>A</em> + <em>B</em>)/11

Similarly, you can eliminate <em>X</em> by using

-3<em>A</em> + 2<em>B</em> = -3 (2<em>X</em> + <em>Y</em>) + 2 (3<em>X</em> - 4<em>Y</em>) = -11<em>Y</em>

==> <em>Y</em> = (3<em>A</em> - 2<em>B</em>)/11

It follows that

$X=\dfrac4{11}\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\dfrac1{11}\begin{bmatrix}7&-10\\-7&11\end{bmatrix} \\\\ X=\dfrac1{11}\left(4\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\left(\begin{bmatrix}48&-12\\40&88\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\begin{bmatrix}55&-22\\33&99\end{bmatrix} \\\\ X=\begin{bmatrix}5&-2\\3&9\end{bmatrix}$

Similarly, you would find

$Y=\begin{bmatrix}2&1\\4&4\end{bmatrix}$

You can solve the second system in the same fashion. You would end up with

$P=\begin{bmatrix}2&-3\\0&1\end{bmatrix} \text{ and } Q=\begin{bmatrix}1&2\\3&-1\end{bmatrix}$

3 0

3 years ago

A rectangle and a triangle have the same area, 72 . The height of the triangle is also the same as the width of the rectangle. T

emmasim [6.3K]

Answer:

Part 1) The height of triangle is $h=8\ in$

Part 2) The width of rectangle is $W=8\ in$

Step-by-step explanation:

step 1

Find the dimensions of triangle

The area of triangle is equal to

$A=\frac{1}{2}bh$

we have

$b=18\ in$

$A=72\ in^{2}$

substitute and solve for h

$72=\frac{1}{2}(18)h$

$144=(18)h$

$h=144/18=8\ in$

step 2

Find the missing dimension of rectangle

we have that

The height of the triangle is the same as the width of the rectangle

therefore

$W=h=8\ in$

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3 years ago

QUESTION IS DOW BELOW 5 POINTS EACH PLEASE HELP PLEASE HELP PLEASE HELP

____ [38]

The central angle in the circle is ∠DAC,major arc is BED, minor arc is ADC and BC=(5π*BD)/18.

Given that BD is diameter of the circle and angle BAC is 100°.

We are required to find the central angle, major arc, minor arc, m BEC, BC.

Angle is basically finding out the intensity of inclination of something on the surface.

In the circle central angles are many like BAC and CAD. We can write CAD as DAC also.

Major arc of a circle is that arc whose length is larger than all other arcs in the circle.

In our circle the major arc is arc BED.

Minor arc of a circle is that arc whose length is smaller.

In our circle the minor arc is arc ADC.

We know that arc's length is 2πr(Θ/360)

In this way BC=2π*(BD/2)*100/360

=(5π*BD)/18

We cannot find angle BEC.

Hence the central angle in the circle is ∠DAC,major arc is BED, minor arc is ADC and BC=(5π*BA)/18.

Learn more about angles at brainly.com/question/25716982

#SPJ1

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2 years ago

What are the solutions of the inequality? Check the solutions. 4x + 6 < –6

topjm [15]

4x+6<-6
4x<-6-6
4x<-12
x<-12/4
x< -3
<span>answer : </span><span>C. x < –3
</span>

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4 years ago

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